Test each equation for symmetry with respect to the x-axis, the y-axis, and the origin.

$2x=3y^2$.

We have given the following equation :-

$2x=3y^2$.

We have to check the symmetry of this equation with respect to x-axis, y-axis and the origin.

The given equation is :-

$2x=3y^2$.

We know that a graph is symmetrical about x-axis, if a point $\left(x,y\right)$lies on graph, then $\left(x,-y\right)$is also lies on graph.

So to check symmetry about x-axis, change $y$by $-y$in the given equation, then we have :-

localid="1646232856419" $$\begin{gathered} 2x=3{(-y)}^2 \\ \Rightarrow 2x=3y^2 \end{gathered}$$

The resulting equation is same as the given equation.

So we can say that the given equation is symmetric about x-axis.

The given equation is :-

$2x=3y^2$.

We know that a graph is symmetrical about y-axis, if a point localid="1646233727617" $\left(x,y\right)$lies on graph, then localid="1646233736168" $\left(-x,y\right)$is also lies on graph.

So to check symmetry about y-axis, change localid="1646233959936" $x$by $-x$in the given equation, then we have :-

$$\begin{gathered} 2\left(-x\right)=3y^2 \\ \Rightarrow -2x=3y^2 \end{gathered}$$

This resulting equation is not same as the given equation.

So we can conclude that given equation is not symmetric about y-axis.

The given equation is :-

$2x=3y^2$.

We know that a graph is symmetrical about origin, if a point $\left(x,y\right)$lies on graph, then $\left(-x,-y\right)$is also lies on graph.

So to check symmetry about origin, change $x$by $-x$and $y$by $-y$in the given equation, then we have :-

localid="1646233539839" $$\begin{gathered} 2(-x)=3{(-y)}^2 \\ \Rightarrow -2x=3y^2 \end{gathered}$$

This resulting equation is not same as given equation.

So we can conclude that the given equation is not symmetric about origin.