Chapter 1: Q 12. (page 51)

Find the center and radius of the circle
$x^{2} + y^{2} + 4 x - 2 y - 4 = 0$ .Graph this circle.

Short Answer

Expert verified

Center and radius are $(- 2, 1)$ and $3$ .

Graph of the equation shown below.

Step by step solution

Step 1. Given information.

Consider the given equation of the circle .

$x^{2} + y^{2} + 4 x - 2 y - 4 = 0$

Step 2. Using the standard form of circle to rewrite the given equation in standard form.x-h2+y-k2=r2 where h,k are the center and r is radius.

$x^{2} + 4 x - 2 y - 4 + y^{2} = 0 {(x - (- 2))}^{2} + {(y - 1)}^{2} = 3^{2}$

Therefore the circle properties .role="math" localid="1646038737236" $(h, k) = (- 2, 1)$ and $r = 3$

Ste[p 3. Plot the graph.

The graph of the given equation is shown below.

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Find the center and radius of the circle
$x^{2} + y^{2} + 4 x - 2 y - 4 = 0$ .Graph this circle.

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Using the standard form of circle to rewrite the given equation in standard form.x-h2+y-k2=r2 where h,k are the center and r is radius.

Ste[p 3. Plot the graph.

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Find the center and radius of the circlex2+y2+4x-2y-4=0.Graph this circle.

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Using the standard form of circle to rewrite the given equation in standard form.x-h2+y-k2=r2 where h,k are the center and r is radius.

Ste[p 3. Plot the graph.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

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Study anywhere. Anytime. Across all devices.

Find the center and radius of the circle
$x^{2} + y^{2} + 4 x - 2 y - 4 = 0$ .Graph this circle.