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Chapter 1: Q 28. (page 51)

Find the standard form of the equation of the circle whose center and radius are given.
$(h, k) = (- 2, 3)$ and $r = 4$ $r = 4$

Short Answer

Expert verified

Standard form is ${(x + 2)}^{2} + {(y - 3)}^{2} = 16$ .

Step by step solution

01

Step 1. Given information.

Consider the given center and radius .

02

Step 2. Formula used.

To find the standard equation of circle use the formula.

${(x - h)}^{2} + {(y - k)}^{2} = r^{2} {(x + 2)}^{2} + {(y - 3)}^{2} = 4^{2}$

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Most popular questions from this chapter

To solve an equation of the form {expression in x = 0}

using a graphing utility, we graph $Y_{1}$ = {expression in x}

and use ________ to determine each x-intercept of the

graph.

Graph the line containing the point P and having slope m.

$P (0, 3), m = u n d e f i n e d$

The equation $2 x - y = C$ defines a family of lines, one line for each value of $C$ . On one set of coordinate axes, graph the members of the family when $C = - 4, C = 0$ and $C = 2$ . Can you draw a conclusion from the graph about each member of the family?

In Problem 17-36, solve each equation algebraically. Verify your solution using a graphing utility.

$3 x^{2} = 4 x + 4$

In Problem 17-36, solve each equation algebraically. Verify your solution using a graphing utility.

$\sqrt{x + 1} = 4$

See all solutions

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