Chapter 1: Q 4. (page 51)

Use a graphing utility to approximate the real solution of equation rounded to two decimal place . All solution lie between $- 10$ and $10$ .
Equation is $2 x^{3} - x^{2} - 2 x + 1 = 0$ .

Short Answer

Expert verified

The root of the given equation are $\frac{1}{2}, \pm 1$ .The graph is shown below.

Step by step solution

Ste[p 1. Given information.

Consider the given equation . $2 x^{3} - x^{2} - 2 x + 1 = 0$

Step 2. Find the root of the given equation.

To find the root of the equation simplify the given equation.

$x^{2} (2 x - 1) - 1 (2 x - 1) (2 x - 1) = 0, (x^{2} - 1) = 0 x = \frac{1}{2}, x = \pm 1$

Step 3. Plot the graph.

The graph of the given equation using graphic utility as shown below.

Equation $2 x^{3} - x^{2} - 2 x + 1 = 0$ .

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Use a graphing utility to approximate the real solution of equation rounded to two decimal place . All solution lie between $- 10$ and $10$ .
Equation is $2 x^{3} - x^{2} - 2 x + 1 = 0$ .

Short Answer

Step by step solution

Ste[p 1. Given information.

Step 2. Find the root of the given equation.

Step 3. Plot the graph.

One App. One Place for Learning.

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Use a graphing utility to approximate the real solution of equation rounded to two decimal place . All solution lie between -10and 10.Equation is2x3-x2-2x+1=0.

Short Answer

Step by step solution

Ste[p 1. Given information.

Step 2. Find the root of the given equation.

Step 3. Plot the graph.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Pure Maths

Decision Maths

Discrete Mathematics

Probability and Statistics

Mechanics Maths

Logic and Functions

Study anywhere. Anytime. Across all devices.

Use a graphing utility to approximate the real solution of equation rounded to two decimal place . All solution lie between $- 10$ and $10$ .
Equation is $2 x^{3} - x^{2} - 2 x + 1 = 0$ .