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Chapter 1: Q. 43 (page 41)

Find an equation of the line L.

Short Answer

Expert verified

The equation of line is $x + 2 y = 5$

Step by step solution

01

Step 1. Given Information

The given graph is

02

Step 2. Explanation

From the given figure, we know the line is perpendicular to line $y = 2 x$

On comparing with the equation of line, we get the slope of line as 2 and as lines are perpendicular so the slope of the other line will be negative reciprocal of 2 which is $- \frac{1}{2}$

Substitute the values in the general form of equation of slope- line format.

role="math" localid="1645947319658" $y - y_{1} = m (x - x_{1}) y - 2 = - \frac{1}{2} (x - 1) y - 2 = - \frac{x}{2} + \frac{1}{2} y = - \frac{x}{2} + \frac{5}{2} 2 y = - x + 5 x + 2 y = 5$

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Most popular questions from this chapter

Find the midpoint of the line segment joining the points P₁ and P₂ .

$P_{1} = (3, - 4); P_{2} = (5, 4)$

In Problem 17-36, solve each equation algebraically. Verify your solution using a graphing utility.

$(x + 2) (x - 3) = {(x - 3)}^{2}$

In Problem 17-36, solve each equation algebraically. Verify your solution using a graphing utility.

$\sqrt{x - 2} = 3$

Plot the points $(0, 3), (1, 3), (- 2, 3), (5, 3),$ and $(- 4, 3)$ . Describe the set of all points of the form $(x, 3)$ , where x is a real number.

Determine the coordinates of the points shown. Tell in which quadrant each point lies. Assume the coordinates are integers.

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