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Chapter 1: Q 7. (page 50)

Find the center and radius of the circle. Write the standard form of the equation.

Short Answer

Expert verified

Center is 2,1.

Radius is equal to 2units.

Standard form of the equation is(x-2)2+(y-1)2=4.

Step by step solution

01

Step 1. Given information

Figure of a circle is given as follows:

02

Step 2. Find the center and radius of a circle.

Radius is the distance between the center and any point on the circle

In this case, radius is the distance between the points (0,1)and (2,1)

Radius=(0-2)2+(1-1)2

=4+0=4=2

From the given graph, we can see that the center is 2,1.

03

Step 3. Find the standard form of the equation.

Equation of a circle with center h,kand radius ris (x-h)2+(y-k)2=r2

Therefore, equation of the circle with center 2,1and radius 2is

(x-2)2+(y-1)2=22(x-2)2+(y-1)2=4

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Most popular questions from this chapter

True or False

In using a graphing utility to solve an

equation, exact solutions are always obtained.

Find the midpoint of the line segment joining the points P1 and P2 .

P1=(a,a);P2=(0,0)

To solve an equation of the form {expression in x = 0}

using a graphing utility, we graph Y1= {expression in x}

and use ________ to determine each x-intercept of the

graph.

Show that the line containing the points (a, b) and (b, a), a b, is perpendicular to the line y = x. Also show that the midpoint of (a, b) and (b, a) lies on the line y = x.

Graph the line containing the point P and having slope m.

P(0,3),m=undefined
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