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Chapter 1: Q28. (page 51)

Find the standard form of the equation of the circle whose center and radius are given.
$(h, k) = (- 2, 3)$ and $r = 4$

Short Answer

Expert verified

The standard form of the circle is .

$x^{2} + y^{2} + 4 x - 6 y = 3$

Step by step solution

01

Step 1. Given information.

Consider the given center and radius are $(h, k) = (- 2, 3)$ and $r = 4$ .

02

Step 2. Standard form of the circle is.

${(x - h)}^{2} + {(y - k)}^{2} = r^{2} {(x + 2)}^{2} + {(y - 3)}^{2} = 4^{2} x^{2} + y^{2} + 4 x - 6 y + 13 = 16 x^{2} + y^{2} + 4 x - 6 y = 3$

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