Chapter 1: Q29. (page 51)

Find the standard form of the equation of the circle whose center and radius are given.
$(h, k) = (- 1, - 2)$ and $r = 1$

Short Answer

Expert verified

The standard form of the circle is .

$x^{2} + y^{2} + 2 x + 4 y = - 4$

Step by step solution

Step 1. Given information.

Consider the given center and radius of the circle $(h, k) = (- 1, - 2)$ and $r = 1$ .

Step 2. The standard form of the equation of circle is x-h2+y-k2=r2.

${(x + 1)}^{2} + {(y + 2)}^{2} = 1^{2} x^{2} + 1 + 2 x + y^{2} + 4 + 4 y = 1 x^{2} + y^{2} + 2 x + 4 y + 5 = 1 x^{2} + y^{2} + 2 x + 4 y = - 4$

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Find the standard form of the equation of the circle whose center and radius are given.
$(h, k) = (- 1, - 2)$ and $r = 1$

Short Answer

Step by step solution

Step 1. Given information.

Step 2. The standard form of the equation of circle is x-h2+y-k2=r2.

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Find the standard form of the equation of the circle whose center and radius are given.h,k=-1,-2andr=1

Short Answer

Step by step solution

Step 1. Given information.

Step 2. The standard form of the equation of circle is x-h2+y-k2=r2.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

Mechanics Maths

Decision Maths

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Study anywhere. Anytime. Across all devices.

Find the standard form of the equation of the circle whose center and radius are given.
$(h, k) = (- 1, - 2)$ and $r = 1$