Chapter 3: Q. 2 (page 155)

Find the real solutions of the equation $2 x^{2} + 7 x - 4 = 0$ .

Short Answer

Expert verified

The real solutions of the given equation are $- 4$ and 0.5.

Step by step solution

Step 1. Given information.

The given quadratic equation is:

$2 x^{2} + 7 x - 4 = 0$

Step 2. Solve the equation.

Spite the middle term and rewrite the given equation.

$\begin{array}{rcl} 2 x^{2} + 8 x - x - 4 & = & 0 \\ 2 x (x + 4) - (x + 4) & = & 0 \\ (x + 4) (2 x - 1) & = & 0 \end{array}$

Use zero product property.

$\begin{array}{rcl} x + 4 & = & 0 and 2 x - 1 = 0 \\ x & = & - 4 and x = \frac{1}{2} \\ x & = & - 4 and x = 0.5 \end{array}$

Step 3. Conclusion.

The real solutions of the given equation are $- 4$ and 0.5.

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Find the real solutions of the equation $2 x^{2} + 7 x - 4 = 0$ .

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Solve the equation.

Step 3. Conclusion.

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Find the real solutions of the equation 2x2+7x-4=0.

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Solve the equation.

Step 3. Conclusion.

One App. One Place for Learning.

Most popular questions from this chapter

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Study anywhere. Anytime. Across all devices.

Find the real solutions of the equation $2 x^{2} + 7 x - 4 = 0$ .