Suppose that fx=x2+4x-21.

(a) What is the vertex of f?

(b) What are the x-intercepts of the graph of f?

(c) Solvefx=-21for x. What points are on the graph of f?

(d) Use the information obtained in parts (a) – (c) to graphfx=x2+4x-21.

Short Answer

Expert verified

(a) Vertex is-2,-25.

(b) x- intercept is x=3,x=7.

(c) The points 0,-2,-4,-21are on the graph of the function f.

(d) The graph offxis,

Step by step solution

01

Part (a) Step 1. Given information

It is given thatfx=x2+4x-21,we need to write the vertex off.

02

Step 2. Simplify

fx=x2+4x-21.

fx=x2+4x+4-4-21.

=x+22-25.

The vertex is-2,-25.

03

Part (b) Step 1. Given information

It is given that fx=x2+4x-21,we need to write thex- intercept of the graph off.

04

Step 2. Simplify

Put fx=0.

x2+4x-21=0.

x=-4±42-4·1-212·1.

=-4±16+842.

=-4±1002.

=-4±102.

x=-4+102=3,x=-4-102=7.

x-intercept isx=3,x=7.

05

Part (c) Step 1. Given information

It is given that fx=x2+4x-21,we need to solve fx=-21forxamd also the points are on the graph.

06

Step 2. Solving

fx=-21.

x2+4x-21=-21.

x2+4x=0.

xx+4=0.

x0,x+4=0.

x=-4.

When x=0orx=-4, the values of the function is -21.

The points0,-21,-4,-21are on the graph of the functionf.

07

Part (d) Step 1. Given information

It is given thatfx=x2+4x-21,we need to use the information of part a-c to graph thefx.

08

Step 2. Graph of fx

The graph of

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