Chapter 9: Q. 15 (page 632)

In Problems 14–18, $P_{1} = (3 \sqrt{2}, 7 \sqrt{2})$ and $P_{2} = (8 \sqrt{2}, 2 \sqrt{2})$ .
Find $||v||$

Short Answer

Expert verified

The answer is $||v|| = 10$

Step by step solution

Step 1. Given information

The points are

$P_{1} = (3 \sqrt{2}, 7 \sqrt{2}) P_{2} = (8 \sqrt{2}, 2 \sqrt{2})$

Step 2. Find v

The position vector $v$ is

$v = <P_{2} - P_{1}> v = <(8 \sqrt{2} - 3 \sqrt{2}), (2 \sqrt{2} - 7 \sqrt{2})> v = <5 \sqrt{2}, - 5 \sqrt{2}>$

Now,

$||v|| = \sqrt{{(5 \sqrt{2})}^{2} + {(- 5 \sqrt{2})}^{2}} ||v|| = \sqrt{50 + 50} ||v|| = \sqrt{100} ||v|| = 10$

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In Problems 14–18, $P_{1} = (3 \sqrt{2}, 7 \sqrt{2})$ and $P_{2} = (8 \sqrt{2}, 2 \sqrt{2})$ .
Find $||v||$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Find v

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In Problems 14–18, P1=32,72and P2=82,22.Findv

Short Answer

Step by step solution

Step 1. Given information

Step 2. Find v

One App. One Place for Learning.

Most popular questions from this chapter

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Study anywhere. Anytime. Across all devices.

In Problems 14–18, $P_{1} = (3 \sqrt{2}, 7 \sqrt{2})$ and $P_{2} = (8 \sqrt{2}, 2 \sqrt{2})$ .
Find $||v||$