Chapter 9: Q. 19 (page 632)

In Problems 19–22, $v_{1} = <4, 6>, v_{2} = <- 3, - 6>, v_{3} = <- 8, 4>, v_{4} = <10, 15>$ .
Find the vector $v_{1} + 2 v_{2} - v_{3}$ .

Short Answer

Expert verified

$v_{1} + 2 v_{2} - v_{3} = 6 \hat{i} - 10 \hat{j}$ or $<6, - 10>$

Step by step solution

Step 1. Given information

The given vectors are

$v_{1} = <4, 6>, v_{2} = <- 3, - 6>, v_{3} = <- 8, 4>, v_{4} = <10, 15>$

Step 2. Find the value of v1+2v2-v3

$v_{1} + 2 v_{2} - v_{3} = 4 \hat{i} + 6 \hat{j} + 2 (- 3 \hat{i} - 6 \hat{j}) - (- 8 \hat{i} + 4 \hat{j}) = 4 \hat{i} + 6 \hat{j} - 6 \hat{i} - 12 \hat{j} + 8 \hat{i} - 4 \hat{j} = 6 \hat{i} - 10 \hat{j}$

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In Problems 19–22, $v_{1} = <4, 6>, v_{2} = <- 3, - 6>, v_{3} = <- 8, 4>, v_{4} = <10, 15>$ .
Find the vector $v_{1} + 2 v_{2} - v_{3}$ .

Short Answer

Step by step solution

Step 1. Given information

Step 2. Find the value of v1+2v2-v3

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In Problems 19–22, v1=4,6,v2=-3,-6,v3=-8,4,v4=10,15.Find the vector v1+2v2-v3.

Short Answer

Step by step solution

Step 1. Given information

Step 2. Find the value of v1+2v2-v3

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

Mechanics Maths

Statistics

Theoretical and Mathematical Physics

Applied Mathematics

Decision Maths

Study anywhere. Anytime. Across all devices.

In Problems 19–22, $v_{1} = <4, 6>, v_{2} = <- 3, - 6>, v_{3} = <- 8, 4>, v_{4} = <10, 15>$ .
Find the vector $v_{1} + 2 v_{2} - v_{3}$ .