Chapter 9: Q. 22 (page 632)

In Problems 19–22, $v_{1} = <4, 6>, v_{2} = <- 3, - 6>, v_{3} = <- 8, 4>, v_{4} = <10, 15>$
Find the angle between vectors $v_{1}$ and $v_{2}$ .

Short Answer

Expert verified

The angle between vectors $v_{1}$ and $v_{2}$ is $172.87 °$

Step by step solution

Step 1. Given information

The given vectors are

$v_{1} = <4, 6>, v_{2} = <- 3, - 6>, v_{3} = <- 8, 4>, v_{4} = <10, 15>$

Step 2. Find the angle between v1 and v2.

$\cos θ = \frac{v_{1} \cdot v_{2}}{||v_{1}|| ||v_{2}||} = \frac{- 12 + (- 36)}{(\sqrt{4^{2} + 6^{2}}) (\sqrt{{(- 3)}^{2} + {(- 6)}^{2}})} = \frac{- 48}{\sqrt{52} \times \sqrt{45}} = - 0.9923 θ = \cos^{- 1} (- 0.9923) θ = 172.87 °$

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In Problems 19–22, $v_{1} = <4, 6>, v_{2} = <- 3, - 6>, v_{3} = <- 8, 4>, v_{4} = <10, 15>$
Find the angle between vectors $v_{1}$ and $v_{2}$ .

Short Answer

Step by step solution

Step 1. Given information

Step 2. Find the angle between v1 and v2.

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In Problems 19–22, v1=4,6,v2=-3,-6,v3=-8,4,v4=10,15Find the angle between vectors v1 and v2 .

Short Answer

Step by step solution

Step 1. Given information

Step 2. Find the angle between v1 and v2.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Decision Maths

Logic and Functions

Theoretical and Mathematical Physics

Mechanics Maths

Pure Maths

Geometry

Study anywhere. Anytime. Across all devices.

In Problems 19–22, $v_{1} = <4, 6>, v_{2} = <- 3, - 6>, v_{3} = <- 8, 4>, v_{4} = <10, 15>$
Find the angle between vectors $v_{1}$ and $v_{2}$ .