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Chapter 9: Q. 3 (page 632)

Find an equation for the circle with a center at the point
$(0, 1)$ and radius $3$ . Graph this circle.

Short Answer

Expert verified

Equation is $x^{2} + {(y - 1)}^{2} = 9$

Step by step solution

01

Step 1. The given information is

Centre at $(0, 1)$ and radius $3$

02

Step 2. Radius is r=(x-h)2+(y-k)2center is (h,k)=(0,1)

$3 = \sqrt{{(x - 0)}^{2} + {(y - 1)}^{2}} 3^{2} = x^{2} + {(y - 1)}^{2} 9 = x^{2} + {(y - 1)}^{2}$

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Most popular questions from this chapter

In Problems, the vector v has initial point P and terminal point Q. Write v in the form ai + bj; that is, find its position vector.

$P = (3, 2); Q = (5, 6)$

If the rectangular coordinates of a point are $(4, - 6),$ the point symmetric to it with respect to the origin is ______.

Write the expression in the standard form $a + b i$ .

${[\sqrt{3} (\cos 10 ° + i \sin 80 °)]}^{3}$

In Problems 13–28, transform each polar equation to an equation in rectangular coordinates. Then identify and graph the equation. Verify your graph using a graphing utility.

$θ = \frac{π}{3}$

Identify and graph each polar equation. Verify your graph using a graphing utility.

$r = 3^{θ}$

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