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Chapter 9: Q. 4 (page 591)

Find the value
$S i n 120^{\circ} =_C o s 240^{\circ} =_$

Short Answer

Expert verified

The answer to the expression is

$\sin 120^{\circ} = 0.866 \cos 240^{\circ} = - 0.5$

Step by step solution

01

Step 1. Given

Trigonometric expressions.

$\sin 120^{\circ} & \cos 240^{\circ}$

02

Step 2. Calculation

Using trigonometric identities we get

$\sin 120^{\circ} = \sin (90 + 30) = \cos 30 = \frac{\sqrt{3}}{2} = 0.866$

Similarly

$\cos 240^{\circ} = \cos (180 + 60) = - \cos (60) = - \frac{1}{2} = - 0.5$

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Most popular questions from this chapter

Identify and graph each polar equation. Verify your graph using a graphing utility.
$r = 3 \cos (2 θ)$

Identify and graph each polar equation. Verify your graph using a graphing utility.

$r = 3 + \cos θ$

In Problems 13–28, transform each polar equation to an equation in rectangular coordinates. Then identify and graph the equation. Verify your graph using a graphing utility.

$r = 4$

Find a vector $v$ whose magnitude is $4$ and whose component

in the $i$ direction is twice the component in the $j$ direction.

Write the expression in the standard form $a + b i$ .

${[4 (\cos 40 ° + i \sin 40 °)]}^{3}$

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