Volume of a Parallelepiped A parallelepiped is a prism whose faces are all parallelograms. Let A, B, and C be the vectors that define the parallelepiped shown in the figure. The volume V of the parallelepiped is given by the formula

V=(A×B).C

Find the volume of a parallelepiped if the defining vectors are

A=3i^-2j^+4k^B=2i^+j^-2k^C=3i^-6j^-2k^

Short Answer

Expert verified

The volume is :

98cubicunits

Step by step solution

01

Step 1. given vectors

A=3i^-2j^+4k^B=2i^+j^-2k^C=3i^-6j^-2k^

02

Step 2. Volume of parallelopiped 

As given in question volume of parallelopiped is given by :

V=(A×B).C

So , Using this :

A=3i^-2j^+4k^B=2i^+j^-2k^C=3i^-6j^-2k^V=(A×B).CV=|((3i^-2j^+4k^)×(2i^+j^-2k^)).(3i^-6j^-2k^)|V=|(0i^+14j^+7k^)>(3i^-6j^-2k^)|V=|-84-14|V=98cubicunits

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