Chapter 4: Q. 10 (page 247)

Find the center and radius of the circle $x^{2} + 4 x + y^{2} - 2 y - 4 = 0 .$ Graph the circle.

Short Answer

Expert verified

The radius and center of circle is 3units and $(- 2, 1)$ respectively

The graph can be given as

Step by step solution

Given information

The equation of the circle is $x^{2} + 4 x + y^{2} - 2 y - 4 = 0 .$

Arrange the equation

We get

$x^{2} + 4 x + y^{2} - 2 y - 4 = 0 . x^{2} + 4 x + 4 + y^{2} - 2 y + 1 - 4 - 1 = 4 {(x + 2)}^{2} + {(y - 1)}^{2} = 9 (x + 2)^{2} + {(y - 1)}^{2} = 3^{2}$

Find the radius and center

On comparing with standard equation we get $r a d i u s = 3$ and center $= (- 2, 1)$

Plot the graph

The graph can be given as

Conclusion

The radius of the circle is 3 units and center is $(- 2, 1)$

The graph of the circle is

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Find the center and radius of the circle $x^{2} + 4 x + y^{2} - 2 y - 4 = 0 .$ Graph the circle.

Short Answer

Step by step solution

Given information

Arrange the equation

Find the radius and center

Plot the graph

Conclusion

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Find the center and radius of the circle x2+4x+y2-2y-4=0.Graph the circle.

Short Answer

Step by step solution

Given information

Arrange the equation

Find the radius and center

Plot the graph

Conclusion

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Theoretical and Mathematical Physics

Logic and Functions

Calculus

Mechanics Maths

Probability and Statistics

Pure Maths

Study anywhere. Anytime. Across all devices.

Find the center and radius of the circle $x^{2} + 4 x + y^{2} - 2 y - 4 = 0 .$ Graph the circle.