form a polynomial function f(x) with real coefficients having the given degree and zeros. Answers will vary depending on the choice of the leading coefficient. Use a graphing utility to graph the function and verify the result.

Degree 4; zeros: 1 multiplicity 3 ; 1+i

Short Answer

Expert verified

The polynomial can be given asf(x)=x5-5x4+11x3+13x2+8x-2

Step by step solution

01

Given information

We are given the degree of polynomial to be 5 the zeros are 1+i and 1 with multiplicity 3

02

Find the equation

As 1+i is one of the roots of the polynomial by conjugate property 1-i is also a root of the polynomial

Hence,

f(x)=(x-1)(x-1)(x-1)(x-(1+i))(x-(1-i))f(x)=(x-1)3((x-1)2+1)f(x)=(x3-3x2+3x-1)(x2-2x+2)f(x)=x5-5x4+11x3+13x2+8x-2

03

Conclusion

The polynomial can be given asf(x)=x5-5x4+11x3+13x2+8x-2

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