Solve each inequality algebraically.

x(x2+1)(x-2)(x-1)(x+1)0

Short Answer

Expert verified

Solution to the inequality x(x2+1)(x-2)(x-1)(x+1)0is (-,-1)[0,1)[2,).

Step by step solution

01

Step 1. Given information  

We have been given an inequality x(x2+1)(x-2)(x-1)(x+1)0.

We have to solve this inequality algebraically.

02

Step 2. Determine the real numbers at which the expression f equals zero and at which the expression f is undefined.  

Assume f(x)=x(x2+1)(x-2)(x-1)(x+1).

x=0x2+1=0Thereisnosuchrealx.x-2=0x=2x-1=0x=1x+1=0x=-1

03

Step 3. Form the intervals  

Using the values of x found in previous step, we can divide the real numbers in the intervals:

(-,-1)(-1,0)(0,1)(1,2)(2,)

04

Step 4. Select a number in each interval and evaluate f at the number  

Create the following table:

Interval(-,-1)
(-1,0)
(0,1)
(1,2)
(2,)
Number chosen-2
-0.5
0.5
1.5
4
Value of f
f(-2)=403
f(-0.5)=-2.08
f(0.5)=1.25
f(1.5)=-1.95
f(4)=13615
Conclusionpositivenegativepositive
negativepositive
05

Step 5. Identify the interval 

Since we want to know where f is positive or zero, we conclude that f(x)0in the interval (-,-1)[0,1)[2,).

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