Chapter 12: Q. 2 (page 838)

In Problems 1– 4, write down the first five terms of each sequence.
$\{c_{n}\} = \{\frac{2^{n}}{n^{2}}\}$

Short Answer

Expert verified

First five terms of the sequence: $2, 1, \frac{8}{9}, 1, \frac{32}{25}$ .

Step by step solution

Given information.

General term of the sequence:

$\{c_{n}\} = \{\frac{2^{n}}{n^{2}}\}$

Step 2. Substitute first five integral value of n in the expression cn and solve.

First term is:

$c_{1} = \frac{2^{1}}{1^{2}} = 2$

Second term:

$c_{2} = \frac{2^{2}}{2^{2}} = 1$

Third term:

$c_{3} = \frac{2^{3}}{3^{2}} = \frac{8}{9}$

Fourth term:

$c_{4} = \frac{2^{4}}{4^{2}} = 1$

Fifth term:

$c_{5} = \frac{2^{5}}{5^{2}} = \frac{32}{25}$

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In Problems 1– 4, write down the first five terms of each sequence.
$\{c_{n}\} = \{\frac{2^{n}}{n^{2}}\}$

Short Answer

Step by step solution

Given information.

Step 2. Substitute first five integral value of n in the expression cn and solve.

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In Problems 1– 4, write down the first five terms of each sequence.cn=2nn2

Short Answer

Step by step solution

Given information.

Step 2. Substitute first five integral value of n in the expression cn and solve.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

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Study anywhere. Anytime. Across all devices.

In Problems 1– 4, write down the first five terms of each sequence.
$\{c_{n}\} = \{\frac{2^{n}}{n^{2}}\}$