Chapter 12: Q 28. (page 808)

In Problems 17–28, write down the first five terms of each sequence.
$\{c_{n}\} = \{\frac{n^{2}}{2^{n}}\}$

Short Answer

Expert verified

The first five terms of the given sequence are $\frac{1}{2}, 1, \frac{9}{8}, 1, \frac{25}{32}$

Step by step solution

Step 1. Write the given sequence.

The given sequence is $\{c_{n}\} = \{\frac{n^{2}}{2^{n}}\}$

Step 2. Find the five terms.

To find the five terms in the sequence we substitute $1, 2, 3, 4 a n d 5 i n t o n$

$\{c_{1}\} = \frac{1^{2}}{2^{1}} = \frac{1}{2} \{c_{2}\} = \frac{2^{2}}{2^{2}} = 1 \{c_{3}\} = \frac{3^{2}}{2^{3}} = \frac{9}{8} \{c_{4}\} = \frac{4^{2}}{2^{4}} = 1 \{c_{5}\} = \frac{5^{2}}{2^{5}} = \frac{25}{32}$

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In Problems 17–28, write down the first five terms of each sequence.
$\{c_{n}\} = \{\frac{n^{2}}{2^{n}}\}$

Short Answer

Step by step solution

Step 1. Write the given sequence.

Step 2. Find the five terms.

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In Problems 17–28, write down the first five terms of each sequence.cn=n22n

Short Answer

Step by step solution

Step 1. Write the given sequence.

Step 2. Find the five terms.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

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Study anywhere. Anytime. Across all devices.

In Problems 17–28, write down the first five terms of each sequence.
$\{c_{n}\} = \{\frac{n^{2}}{2^{n}}\}$