Chapter 11: Q. 23 (page 796)

Graph the system of inequalities:
$\{\begin{cases} x^{2} + y^{2} \leq 100 \\ 4 x - 3 y \geq 0 \end{cases}$

Short Answer

Expert verified

The final graph is

Step by step solution

Step 1. Given information

A system of equation is given as

$\{\begin{cases} x^{2} + y^{2} \leq 100 \\ 4 x - 3 y \geq 0 \end{cases}$

Step 2. Plotting graph

First draw the circle $x^{2} + y^{2} = 100$ ,

Substitute the values of xand yin the first inequality,

$(0)^{2} + (0)^{2} \leq 100 0 < 100$

Therefore the graph is

Step 3. Graph for linear inequality

Now plot the graph of inequality ,

Substitute zero for xand y ,

So the graph of inequality is

Step 4. Final graph

By combining the both graphs of inequality, the final graph is

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Graph the system of inequalities:
$\{\begin{cases} x^{2} + y^{2} \leq 100 \\ 4 x - 3 y \geq 0 \end{cases}$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Plotting graph

Step 3. Graph for linear inequality

Step 4. Final graph

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Graph the system of inequalities:x2+y2≤1004x-3y≥0

Short Answer

Step by step solution

Step 1. Given information

Step 2. Plotting graph

Step 3. Graph for linear inequality

Step 4. Final graph

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Applied Mathematics

Probability and Statistics

Calculus

Theoretical and Mathematical Physics

Statistics

Pure Maths

Study anywhere. Anytime. Across all devices.

Graph the system of inequalities:
$\{\begin{cases} x^{2} + y^{2} \leq 100 \\ 4 x - 3 y \geq 0 \end{cases}$