In Problems 39–43, solve each system of equations.

2xy+y2=103y2-xy=2

Short Answer

Expert verified

Solutions of the system of equations 2xy+y2=103y2-xy=2are22,2

Step by step solution

01

Step 1. Given data 

The given system of equation is

2xy+y2=103y2-xy=2

02

Step 2. Formation of the single-variable equation 

Multiply 2 to both sides of the equation3y2-xy=2

23y2-xy=226y2-2xy=4

so the new system of equation isrole="math" localid="1646947737732" 2xy+y2=106y2-2xy=4

add both equations of the system of equations,

2xy+y2+6y2-2xy=10+47y2=14y=±2

03

Step 4. Solution of the system of equations 

Substitute y=2in equationrole="math" localid="1646947985401" 3y2-xy=2

3y2-xy=2322-x2=2x2=4x=22

Substitute y=-2in equation3y2-xy=2

3y2-xy=23-22-x-2=2x2=-4x=-22

So solutions of the system of equations are22,2&-22,-2

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