Chapter 11: Q. 69 (page 773)

In Problems $65 - 70$ , graph each equation and find the point(s) of intersection, if any.
$y = \frac{4}{x - 3}$ and the circle $x^{2} - 6 x + y^{2} + 1 = 0$ .

Short Answer

Expert verified

The graph of the equation $y = \frac{4}{x - 3}$ and the circle $x^{2} - 6 x + y^{2} + 1 = 0$ is,

From the graph, the intersecting points are, $(5, 2), (1, - 2)$ .

Step by step solution

Step 1. Given information

$y = \frac{4}{x - 3} x^{2} - 6 x + y^{2} + 1 = 0$

First solve each equation for $y$ .

Consider the first equation,

$y = \frac{4}{x - 3}$

Consider the second equation,

$x^{2} - 6 x + y^{2} + 1 = 0 y^{2} + 1 = - x^{2} + 6 x y^{2} = - x^{2} + 6 x - 1 y = \pm \sqrt{- x^{2} + 6 x - 1}$

Step 2 Now sketch a graph for the obtained equations.

In the graph, the two equations are intersecting at two points. They are, $(1, - 2), (5, 2)$ .

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In Problems $65 - 70$ , graph each equation and find the point(s) of intersection, if any.
$y = \frac{4}{x - 3}$ and the circle $x^{2} - 6 x + y^{2} + 1 = 0$ .

Short Answer

Step by step solution

Step 1. Given information

Step 2 Now sketch a graph for the obtained equations.

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In Problems 65-70, graph each equation and find the point(s) of intersection, if any.y=4x-3and the circlex2-6x+y2+1=0.

Short Answer

Step by step solution

Step 1. Given information

Step 2 Now sketch a graph for the obtained equations.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Pure Maths

Probability and Statistics

Calculus

Applied Mathematics

Mechanics Maths

Decision Maths

Study anywhere. Anytime. Across all devices.

In Problems $65 - 70$ , graph each equation and find the point(s) of intersection, if any.
$y = \frac{4}{x - 3}$ and the circle $x^{2} - 6 x + y^{2} + 1 = 0$ .