Chapter 6: Q 128 (page 397)

Show that the period of $f (θ) = c o t θ$ is $π$ .

Short Answer

Expert verified

From the following graph of cotangent function $f (θ) = c o t θ$ it is clear that the period of cotangent function is $π$ .

Step by step solution

Step 1. Given Information

We have to prove that the period of cotangent function is $π$ .

We will draw the graph of this function. After that from the graph we will examine the period of the function.

Step 2. To find period of cotangent function

The given function is :-

$f (θ) = c o t θ$ .

By using graphing utilities, we have the following graph of this function :-

We can see that curve of the graph repeated itself.

We know that the period of a function is where from the graph of function repeated itself.

We can see that the graph from $\frac{π}{2}$ to $\frac{3 π}{2}$ is same as $\frac{3 π}{2}$ to $\frac{5 π}{2}$ , $- \frac{π}{2}$ to $\frac{π}{2}$ and so on.

So we can conclude that the period of this function is :-

$\frac{3 π}{2} - \frac{π}{2} = π$ .

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Show that the period of $f (θ) = c o t θ$ is $π$ .

Short Answer

Step by step solution

Step 1. Given Information

Step 2. To find period of cotangent function

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Show that the period of $f (θ) = c o t θ$ is $π$ .