In Problems 19–26, apply the methods of this and the previous section to graph each function. Be sure to label key points and show at least two periods.

y=-cot(2x+π2)

Short Answer

Expert verified

The graph of the function y=-cot(2x+π2)is:

Step by step solution

01

Step 1. Given

The functiony=-cot(2x+π2)

To graph the function with at least two cycles.

02

Step 2. Find the amplitude, period and phase shift.

Compare the given function y=-cot(2(x-(-π4)))with y=Asin(ωx-ϕ)+B

No amplitude

Period, 2πω=π2

Phase shift, ϕω=-π4

03

Step 3. Determine x-coordinates

One cycle begins at x=ϕω(-π4)and ends at

x=ϕω+2πω=-π4+π2=π4

To find the five key points, divide the interval (-π4,π4)into four sub intervals, each of length π2÷4=π8

-π4+π8=-π8

-π8+π8=0

0+π8=π8

π8+π8=π4

The x-coordinates are -π4,-π8,0,π8,π4

04

Step 4. Determine the key points

Use these values of xto determine the key points on the graph:

The key points include (-π8,-1),(0,0),(-3π8,1),(π8,1),(3π8,-1)

05

Step 5. Sketch the graph

Plot these five points and fill in the graph of the function.

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