Chapter 6: Q. 3 (page 437)

Find an equation for a circle of radius $4$ and center at the point $(0, - 2)$ .

Short Answer

Expert verified

The equation of the circle is $x^{2} + {(y + 2)}^{2} = 16$ .

Step by step solution

Step 1. Given Information

The radius of the circle is $4$ units.

The center of the circle is $(0, - 2)$ .

We need to find the equation of the circle.

Step 2. Finding the equation of the circle

Equation of a circle with radius $r$ units and center at $(h, k)$ is given by ${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ .

Here, $h = 0, k = - 2, r = 4$ .

Equation of the required circle is:

role="math" localid="1646377000748" ${(x - 0)}^{2} + (y - {(- 2))}^{2} = {(4)}^{2} \Rightarrow x^{2} + {(y + 2)}^{2} = 16$

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Find an equation for a circle of radius $4$ and center at the point $(0, - 2)$ .

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Finding the equation of the circle

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Find an equation for a circle of radius 4 and center at the point (0,-2).

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Finding the equation of the circle

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

Pure Maths

Geometry

Calculus

Applied Mathematics

Logic and Functions

Study anywhere. Anytime. Across all devices.

Find an equation for a circle of radius $4$ and center at the point $(0, - 2)$ .