Chapter 6: Q. 49 (page 419)

graph each function
$f (x) = \{\begin{cases} \tan x & 0 \leq x < \frac{π}{2} \\ 0 & x = \frac{π}{2} \\ s e c c & \frac{π}{2} < x \leq π \end{cases}$

Short Answer

Expert verified

The graph of $f (x) = \{\begin{cases} \tan x & 0 \leq x < \frac{π}{2} \\ 0 & x = \frac{π}{2} \\ s e c c & \frac{π}{2} < x \leq π \end{cases}$ is

Step by step solution

Step 1. Given data

The given function is

$f (x) = \{\begin{cases} \tan x & 0 \leq x < \frac{π}{2} \\ 0 & x = \frac{π}{2} \\ s e c c & \frac{π}{2} < x \leq π \end{cases}$

Step 2. Points of f(x)=tan x

Consider different values of x from $[0, \frac{π}{2})$ for $f (x) = \tan x$ and determine several coordinates of points

Step 3. Points of f(x)=sec x

Consider different values of xfrom $(\frac{π}{2}, π)$ for $f (x) = s e c x$ and determine several coordinates of points

Step 4. Graph of the function

Use the coordinates of points and Plot the graph of $f (x) = \{\begin{cases} \tan x & 0 \leq x < \frac{π}{2} \\ 0 & x = \frac{π}{2} \\ s e c c & \frac{π}{2} < x \leq π \end{cases}$

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graph each function
$f (x) = \{\begin{cases} \tan x & 0 \leq x < \frac{π}{2} \\ 0 & x = \frac{π}{2} \\ s e c c & \frac{π}{2} < x \leq π \end{cases}$

Short Answer

Step by step solution

Step 1. Given data

Step 2. Points of f(x)=tan x

Step 3. Points of f(x)=sec x

Step 4. Graph of the function

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graph each functionf(x)=tanx0≤x<π20x=π2seccπ2<x≤π

Short Answer

Step by step solution

Step 1. Given data

Step 2. Points of f(x)=tan x

Step 3. Points of f(x)=sec x

Step 4. Graph of the function

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Probability and Statistics

Theoretical and Mathematical Physics

Applied Mathematics

Logic and Functions

Geometry

Decision Maths

Study anywhere. Anytime. Across all devices.

graph each function
$f (x) = \{\begin{cases} \tan x & 0 \leq x < \frac{π}{2} \\ 0 & x = \frac{π}{2} \\ s e c c & \frac{π}{2} < x \leq π \end{cases}$