Chapter 6: Q.87 (page 396)

use properties of the trigonometric functions to find the exact value of each expression. Do not use a calculator:
$\frac{\sin (- 20^{o})}{\cos (380^{o})} + \tan (200^{o})$

Short Answer

Expert verified

The exact value of $\frac{\sin (- 20^{o})}{\cos (380^{o})} + \tan (200^{o}) i s 0 .$

Step by step solution

Given information

We are given a equation $\frac{\sin (- 20^{o})}{\cos (380^{o})} + \tan (200^{o})$

Use periodicity property of trigonometric functionssinθ+2π=sinθcosθ+2π=cosθtanθ+π=tanθ

We get,

$\frac{\sin (- 20^{o})}{\cos (380^{o})} + \tan (200^{o}) - \frac{\sin (20^{o})}{\cos (20^{o})} + \tan (20^{o}) - \frac{\sin (20^{o})}{\cos (20^{o})} + \frac{\sin (20^{o})}{\cos (20^{o})} = 0$

Conclusion

The exact value of $\frac{\sin (20^{o})}{\cos (20^{o})} + \tan (20^{o}) i s 0 .$

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use properties of the trigonometric functions to find the exact value of each expression. Do not use a calculator:
$\frac{\sin (- 20^{o})}{\cos (380^{o})} + \tan (200^{o})$

Short Answer

Step by step solution

Given information

Use periodicity property of trigonometric functionssinθ+2π=sinθcosθ+2π=cosθtanθ+π=tanθ

Conclusion

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use properties of the trigonometric functions to find the exact value of each expression. Do not use a calculator:sin-20ocos380o+tan200o

Short Answer

Step by step solution

Given information

Use periodicity property of trigonometric functionssinθ+2π=sinθcosθ+2π=cosθtanθ+π=tanθ

Conclusion

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Statistics

Calculus

Theoretical and Mathematical Physics

Applied Mathematics

Probability and Statistics

Discrete Mathematics

Study anywhere. Anytime. Across all devices.

use properties of the trigonometric functions to find the exact value of each expression. Do not use a calculator:
$\frac{\sin (- 20^{o})}{\cos (380^{o})} + \tan (200^{o})$