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Chapter 6: Q.92 (page 396)

if $\cot (θ) = - 2$ find $\cot (θ) + \cot (θ - π) + \cot (θ - 2 π)$

Short Answer

Expert verified

The value of $\cot (θ) + \cot (θ - π) + \cot (θ - 2 π) i s - 6$

Step by step solution

01

Given information

We are given $\cot (θ) = - 2$

02

Use periodicity property of trigonometric function cotθ+π=cotθ

We get,

$\cot (θ) + \cot (θ - π) + \cot (θ - 2 π) \cot (θ) + \cot (θ) + \cot (θ - π) \cot (θ) + \cot (θ) + \cot (θ) 3 \cot (θ) = 3 (- 2) = - 6$

03

Conclusion

The value of $\cot (θ) + \cot (θ - π) + \cot (θ - 2 π) i s - 6$

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Most popular questions from this chapter

Convert each angle in degrees to radians. Express your answer as a multiple of $π$ .

$270 °$

In problems 13-20, $P (x, y)$ is the point on the unit circle that corresponds to a real number $t$ . Find the exact values of the six trigonometric functions of $t$ .

$(- \frac{\sqrt{5}}{3}, - \frac{2}{3})$ .

Use the graph to determine the domain

and the range of function

$y = \tan (\frac{1}{4} x) + 1$

Use a calculator to find the approximate value of each expression rounded to two decimal places: $\cot (\frac{π}{12})$

The domain of the tangent function is _____.

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