Question:Paying for music downloads. If you use the Internet, have you ever paid to access or download music? This was one of the questions of interest in a Pew Internet & American Life Project Survey (October 2010). In a representative sample of 755 adults who use the Internet, 506 admitted

that they have paid to download music. Let p represent the true proportion of all Internet-using adults who have paid to download music.

a. Compute a point estimate of p.

b. Set up the null and alternative hypotheses for testing whether the true proportion of all Internet-using adults who have paid to download music exceeds.7.

c. Compute the test statistic for part b.

d. Find the rejection region for the test if α = 0.01.

e. Find the p-value for the test.

f. Make the appropriate conclusion using the rejection region.

g. Make the appropriate conclusion using the p-value.

Short Answer

Expert verified
  1. The point estimate of p is .
  2. The null and alternative hypotheses are: H0 : p= 0.7 Against Ha : p > 0.7 .
  3. The value of the test statistic is z = -1.72
  4. The rejection region is z > 2.33.
  5. The p-value is 0.9573.
  6. Do not reject the null hypothesis at a 1% significance level. There is no sufficient evidence to say that the true proportion of all Internet-using adults who have paid to download music exceeds 0.7.
  7. Do not reject the null hypothesis. Therefore, there is not enough evidence to claim that the proportion of adults who paid to download music exceeds 0.7.

Step by step solution

01

Given Information

A random sample of 755 adults who use the Internet is taken. Out of these, 506 admitted that they have paid to download music.

Let p represent the true proportion of all Internet-using adults who have paid to download music.

The sample size is 755 is selected from the population. The sample proportion is 0.65.

02

Computing the point estimate of p

(a)

Definition of the point estimate -

It is the estimate of the population parameter in a single value. It represents the point on the number line hence called a point estimate.

The point estimate of the population proportion is the sample proportion .

The value of the sample proportion is:

The point estimate of p is .

03

Setting the null and alternative hypothesis

(b)

The alternative hypothesis generally represents the claim of the researcher. It is complementary to the null hypothesis.

A researcher wants to determine whether the true proportion exceeds 0.7.

The null and alternative hypotheses are: H0 : p= 0.7 Against Ha : p > 0.7 .

04

Computing the test statistic 

(c)

The z-test is used to obtain the test statistic. It is the sampling distribution of sample proportion.

The test statistic is

The value of the test statistic is z = -1.72.

05

Obtaining the rejection region

(d)

The rejection region is obtained by using the critical value. For a right-tailed test, it lies on the right side of the critical value.

Referring to parts a. and b., the point estimate and test statistic are 0.70 and -1.72, respectively.

The z-critical value at a 1% level of significance for a right-tailed test is:

In the z-table, the z-score corresponding to the probability of 0.99 is the required value.

Therefore, the rejection region is z > 2.33.

06

Obtaining the p-value

(e)

Let p represents the true percentage of all adult Internet users who paid to download music.

The p-value is obtained by using the test statistic. For a right-tailed test, the p-value is the probability of getting the test statistic more than the calculated value of the test statistic.

The p-value for the right-tailed test is:

Hence the p-value is 0.9573.

07

Conclusion of the test using the rejection region

(f)

From the hypothesis test, the test statistic is z = -1.72, and the rejection region is z > 2.33.

From the rejection region, the decion regarding the null hypothesis is taken. The null hypothesis is not rejected if the test statistic is outside of the rejection region.

Here the test statistic does not lie in the rejection region. Do not reject the null hypothesis at a 1% significance level.

There is no sufficient evidence to say that the true proportion of all Internet-using adults who have paid to download music exceeds 0.7.

08

Conclusion of the test using the p-value

(g)

The p-value for the test is 0.9573, and the significance level is α = 0.01.

The p-value is used to take the decision about the hypothesis. The null hypothesis is rejected if the significance exceeds the p-value.

The p-value for the test is more significant than 0.05, hence do not reject the null hypothesis.

Therefore, there is not enough evidence to claim that the proportion of adults who paid to download music exceeds 0.7.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the test \({H_0}:\mu = 70\) versus \({H_a}:\mu \ne 70\) using a large sample of size n = 400. Assume\(\sigma = 20\).

a. Describe the sampling distribution of\(\bar x\).

b. Find the value of the test statistic if\(\bar x = 72.5\).

c. Refer to part b. Find the p-value of the test.

d. Find the rejection region of the test for\(\alpha = 0.01\).

e. Refer to parts c and d. Use the p-value approach to

make the appropriate conclusion.

f. Repeat part e, but use the rejection region approach.

g. Do the conclusions, parts e and f, agree?

EPA limits on vinyl chloride. The EPA sets an airborne limit of 5 parts per million (ppm) on vinyl chloride, a colorless gas used to make plastics, adhesives, and other chemicals. It is both a carcinogen and a mutagen (New Jersey Department of Health, Hazardous Substance Fact Sheet, 2010). A major plastics manufacturer, attempting to control the amount of vinyl chloride its workers are exposed to, has given instructions to halt production if the mean amount of vinyl chloride in the air exceeds 3.0 ppm. A random sample of 50 air specimens produced the following statistics: \(\overline x = 3.1\)ppm,\(s = 0.5\)ppm.

a. Do these statistics provide sufficient evidence to halt the production process? Use\(\alpha = 0.01\).

b. If you were the plant manager, would you want to use a large or a small value for\(\alpha \)the test in part a? Explain.

c. Find the p-value for the test and interpret its value

Suppose you are interested in conducting the statistical test of \({H_0}:\mu = 255\) against \({H_a}:\mu > 225\), and you have decided to use the following decision rule: Reject H0 if the sample mean of a random sample of 81 items is more than 270. Assume that the standard deviation of the population is 63.

a. Express the decision rule in terms of z.

b. Find \(\alpha \), the probability of making a Type I error by using this decision rule.

Shopping vehicle and judgment. Refer to the Journal of Marketing Research (December 2011) study of grocery store shoppers’ judgments, Exercise 2.85 (p. 112). For one part of the study, 11 consumers were told to put their arm in a flex position (similar to carrying a shopping basket) and then each consumer was offered several choices between a vice product and a virtue product (e.g., a movie ticket vs. a shopping coupon, pay later with a larger amount vs. pay now). Based on these choices, a vice choice score was determined on a scale of 0 to 100 (where higher scores indicate a greater preference for vice options). The data in the next table are (simulated) choice scores for the 11 consumers. Suppose that the average choice score for consumers with an extended arm position (similar to pushing a shopping cart) is known to be \(\mu = 50\) . The researchers theorize that the mean choice score for consumers shopping with a flexed arm will be higher than 43 (reflecting their higher propensity to select a vice product) Test the theory at \(\alpha = 0.05\)

If the rejection of the null hypothesis of a particular test would cause your firm to go out of business, would you want ato be small or large? Explain

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free