Minority ownership of franchises. According to a 2011 report for IFA Educational Foundation, 20.5% of all franchised businesses in the United States are minority owned. (This information is based on the U.S. Census Bureau’s survey of 27 million business owners.) Suppose that you obtain a sample of 100 franchised businesses located in Mississippi and find that 15 are owned by minorities. Does this result lead you to conclude that the percentage of minority-owned franchises in Mississippi is less than the national value of 20.5%? Explain.

Short Answer

Expert verified

The confidence interval is (0.88,0.22).

No,the result do no lead us to conclude that the percentage of minority-owned franchises in Mississippi is less than the national value of 20.5%.

Step by step solution

01

Given information

According to a 2011 report for IFA Educational Foundation, a sample of 100 franchised businesses located in Mississippi and find that 15 are owned by minorities.

02

Finding the 95% confidence interval

The sample proportion is the point estimator of the population proportion p.

Computing the sample proportion is,

p^=Xn=15100=0.15

Then the level of1001-α%confidence interval for p (proportion) is,

p^±zα2p^1-p^n

For a 95% confidence interval, the value ofα2is,

1001-α%=95%1-α=0.95

For,α=0.05andα2=0.025α=0.05andα2=0.025

The 95% confidence interval is,

p^±zα2p^1-p^n=0.15±1.9600.151-0.15100FromStandardNormalTable=0.15±1.9600.001275=0.15±0.07=0.08,0.02

Therefore, the 95% confidence interval that the true percentage of minority-owned franchises in Mississippi is between 8% and 22%.

Also 20.5% falls in this interval.

Hence, conclude that the percentage of minority-owned franchises in Mississippi is not less than the national value.

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Most popular questions from this chapter

Scallops, sampling, and the law. Interfaces (March–April 1995) presented the case of a ship that fishes for scallops off the coast of New England. In order to protect baby scallops from being harvested, the U.S. Fisheries and Wildlife Service requires that “the average meat per scallop weigh at least 136 of a pound.” The ship was accused of violating this weight standard. Author Arnold Barnett lays out the scenario:

The vessel arrived at a Massachusetts port with 11,000 bags of scallops, from which the harbormaster randomly selected 18 bags for weighing. From each such bag, his agents took a large scoopful of scallops; then, to estimate the bag’s average meat per scallop, they divided the total weight of meat in the scoopful by the number of scallops it contained. Based on the 18 [numbers] thus generated, the harbormaster estimated that each of the ship’s scallops possessed an average of 139 of a pound of meat (that is, they were about seven percent lighter than the minimum requirement). Viewing this outcome as conclusive evidence that the weight standard had been violated, federal authorities at once confiscated 95 percent of the catch (which they then sold at auction). The fishing voyage was thus transformed into a financial catastrophe for its participants. The actual scallop weight measurements for each of the 18 sampled bags are listed in the table below. For ease of exposition, Barnett expressed each number as a multiple of of a pound, the minimum permissible average weight per scallop. Consequently, numbers below 1 indicate individual bags that do not meet the standard. The ship’s owner filed a lawsuit against the federal government, declaring that his vessel had fully complied with the weight standard. A Boston law firm was hired to represent the owner in legal proceedings, and Barnett was retained by the firm to provide statistical litigation support and, if necessary, expert witness testimony.

0.93

0.88

0.85

0.91

0.91

0.84

0.90

0.98

0.88

0.89

0.98

0.87

0.91

0.92

0.99

1.14

1.06

0.93

  1. Recall that the harbormaster sampled only 18 of the ship’s 11,000 bags of scallops. One of the questions the lawyers asked Barnett was, “Can a reliable estimate of the mean weight of all the scallops be obtained from a sample of size 18?” Give your opinion on this issue.
  2. As stated in the article, the government’s decision rule is to confiscate a catch if the sample mean weight of the scallops is less than 136 of a pound. Do you see any flaws in this rule?
  3. Develop your own procedure for determining whether a ship is in violation of the minimum-weight restriction. Apply your rule to the data. Draw a conclusion about the ship in question.

Tipping points in daily deal transactions? Online “daily deal” sites (e.g., Groupon) offer customers a voucher to purchase a product at discount prices. However, the number of voucher purchases must exceed a predetermined number before the deal becomes active. This key number is termed the “tipping point” in marketing. Characteristics of the tipping point were investigated in the Journal of Interactive Marketing (February 2016). A sample of 2,617 vouchers purchased from daily-deal sites in Korea had a mean tipping point of 112 sales with a standard deviation of 560 sales. The researchers want to estimate the true mean tipping point of all daily deal offerings in Korea with 95% confidence. Find and practically interpret this interval estimate.

Describe the sampling distribution of based on large samples of size n—that is, give the mean, the standard deviation, and the (approximate) shape of the distribution of when large samples of size n are (repeatedly) selected fromthe binomial distribution with probability of success p.

A random sample of 70 observations from a normally distributed population possesses a sample mean equal to 26.2 and a sample standard deviation equal to 4.1.

a. Find an approximate 95% confidence interval for

b. What do you mean when you say that a confidence coefficient is .95?

c. Find an approximate 99% confidence interval for

d. What happens to the width of a confidence interval as the value of the confidence coefficient is increased while the sample size is held fixed?

e. Would your confidence intervals of parts a and c be valid if the distribution of the original population was not normal? Explain

Lett0 be a specific value of t. Use Table III in Appendix D to findt0 values such that the following statements are true.

a. Ρ(tt0)=0.025where df=11

b.Ρ(tt0)=0.01 wheredf=9

c.Ρ(tt0)=0.005 wheredf=6

d.Ρ(tt0)=0.05 wheredf=18

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