Do social robots walk or roll? Refer to the International Conference on Social Robotics (Vol. 6414, 2010) study of the trend in the design of social robots, Exercise 5.44 (p. 320). The researchers obtained a random sample of 106 social robots through a Web search and determined that 63 were designed with legs, but no wheels.

a. Find a 99% confidence interval for the proportion of all social robots designed with legs but no wheels. Interpret the result.

b. In Exercise 5.42, you assumed that 40% of all social robots are designed with legs but no wheels. Comment on the validity of this assumption.

Short Answer

Expert verified

a.The 99% confidence interval is0.4715,0.7171

b. The assumption is not valid.

Step by step solution

01

Given information

The researchers discovered a random sample of 106 social robots via a Web search as well as discovered that 63 of them had legs but no wheels. One must calculate the following.

a.99% confidence interval for the proportion of all social robots designed with legs but no wheels

b. Validity of the assumption in exercise 5.42

02

(a) 99% confidence interval for the proportion

Here the confidence coefficient is 99%, henceα=1%.Now from the standard normal distribution table,zα2=2.576

Here sample size is n=106 and x=63, where x is the number of success

The sample proportion is

p^=xn=63106=05943

The margin of error

E=zα2×p^1-p^n=2.576×0.5943×1-0.5943106=0.1228

Hence 99% lower limit:p^-E=0.5943-0.1228=0.4715

99% upper limit:p^+E=0.5943+0.1228=0.7171

The 99% confidence interval is0.4715,0.7171

We are 99% confident that the true proportion lies between the interval0.4715,0.7171

03

(b) Validity of the assumption in the exercise 5.42

The 99% confidence interval is0.4715,0.7171 .Since 40%=0.4 does not contain in the interval, 0.4715,0.7171then the assumption is not valid.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Water pollution testing. The EPA wants to test a randomlyselected sample of n water specimens and estimate themean daily rate of pollution produced by a mining operation.If the EPA wants a 95% confidence interval estimatewith a sampling error of 1 milligram per liter (mg/L),how many water specimens are required in the sample?Assume prior knowledge indicates that pollution readingsin water samples taken during a day are approximately

normally distributed with a standard deviation equal to5 mg/L.

Question: Furniture brand familiarity. A brand name that consumers recognize is a highly valued commodity in any industry. To assess brand familiarity in the furniture industry, NPD (a market research firm) surveyed 1,333 women who head U.S. households that have incomes of $25,000 or more. The sample was drawn from a database of 25,000 households that match the criteria listed above. Of the 10 furniture brands evaluated, La-Z-Boy was the most recognized brand; 70.8% of the respondents indicated they were “very familiar” with La-Z-Boy.

a. Describe the population being investigated by NPD.

b. In constructing a confidence interval to estimate the proportion of households that are very familiar with the La-Z-Boy brand, is it necessary to use the finite population correction factor? Explain.

c. What estimate of the standard error of should be used in constructing the confidence interval of part b?

d. Construct a 90% confidence interval for the true proportion and interpret it in the context of the problem.

Calculate the percentage of the population sampled and

the finite population correction factor for each of the following

situations.

a. n= 1,000, N= 2,500

b. n= 1,000, N= 5,000

c. n= 1,000, N= 10,000

d. n= 1,000, N= 100,000

Accountants’ salary survey. Each year, ManagementAccountingreports the results of a salary survey of themembers of the Institute of Management Accountants(IMA). One year, the 2,112 members responding had a salarydistribution with a 20th percentile of \(35,100; a medianof \)50,000; and an 80th percentile of \(73,000.

  1. Use this information to determine the minimum samplesize that could be used in next year’s survey toestimate the mean salary of IMA members towithin\)2,000 with 98% confidence. [Hint: To estimate s,first applyChebyshev’s Theorem to find ksuch thatat least 60% of the data fall within kstandard deviations of μ. Then find data-custom-editor="chemistry" s(80thpercentile–20thpercentile)/2k.]
  2. Explain how you estimated the standard deviation requiredfor the sample size calculation.
  3. List any assumptions you make.

Lett0 be a specific value of t. Use Table III in Appendix D to findt0 values such that the following statements are true.

a. Ρ(tt0)=0.025where df=11

b.Ρ(tt0)=0.01 wheredf=9

c.Ρ(tt0)=0.005 wheredf=6

d.Ρ(tt0)=0.05 wheredf=18

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free