Identify the rejection region for each of the following cases. Assume v1= 7 andv2= 9

a.Ha12<σ22,α=0.05b.Ha12>σ22,α=.01c.Ha12σ22,α=.1withs12>s22d.Ha12<σ22,α=0.025

Short Answer

Expert verified

A hypothesis is a tested assertion concerning the relation among two or more factors or a suggested reason for an observable phenomenon.

Step by step solution

01

(a) Find the rejected region 

The numerator degrees of freedom isv1=7

The denominator degrees of freedom isv2=9

The alternative hypothesis isHa:σ12<σ22

The level of significance isα=0.05

As the alternative hypothesis is given to us, so we will set up a null hypothesis, that isH0:σ12=σ22

Using percentage points of the F-distributionα=0.05, the critical value is 3.293.

Therefore, the rejection region is F>3.293.

02

(b) Find the rejected region 

The numerator degrees of freedom is V1 =7

The denominator degrees of freedom is V2 = 9

The alternative hypothesis isHa:σ12>σ22

The level of significance isα=0.01

As the alternative hypothesis is given to us, so we will set up a null hypothesis, that isH0:σ12=σ22

Using percentage points of the F-distributionα=0.01, the critical value is

Therefore, the rejection region is F>5.613.

03

(c) Find the rejected region

The numerator degrees of freedom is V1 =7

The denominator degrees of freedom is V2 = 9

The alternative hypothesis isHa:σ12σ22

The level of significance isα=0.1

As the alternative hypothesis is given to us, so we will set up a null hypothesis, that isH0:σ12=σ22

Using percentage points of the F-distributionα=0.1, the critical value is

Therefore, the rejection region is 2,505.

04

(d) Find the rejected region

The numerator degrees of freedom is V1 =7

The denominator degrees of freedom is V2 = 9

The alternative hypothesis isHa:σ12<σ22

The level of significance isα=0.025

As the alternative hypothesis is given to us, so we will set up a null hypothesis, that is H0:σ12=σ22

Using percentage points of the F-distribution α=0.025, the critical value is 4.197

Therefore, the rejection region is F>4.197.

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Most popular questions from this chapter

Optimal goal target in soccer. When attempting to score a goal in soccer, where should you aim your shot? Should you aim for a goalpost (as some soccer coaches teach), the middle of the goal, or some other target? To answer these questions, Chance (Fall 2009) utilized the normal probability distribution. Suppose the accuracy x of a professional soccer player’s shots follows a normal distribution with a mean of 0 feet and a standard deviation of 3 feet. (For example, if the player hits his target,x=0; if he misses his target 2 feet to the right, x=2; and if he misses 1 foot to the left,x=-1.) Now, a regulation soccer goal is 24 feet wide. Assume that a goalkeeper will stop (save) all shots within 9 feet of where he is standing; all other shots on goal will score. Consider a goalkeeper who stands in the middle of the goal.

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Descriptive Statistics: Support

Variables

N

Mean

StDev

Variance

Minimum

Maximum

Range

Support

992

67.755

26.871

722.036

0.000

155.000

155.000

A random sample of size n = 121 yielded p^ = .88.

a. Is the sample size large enough to use the methods of this section to construct a confidence interval for p? Explain.

b. Construct a 90% confidence interval for p.

c. What assumption is necessary to ensure the validity of this confidence interval?

Find a value of the standard normal random variable z, call it z0, such that

a.P(zz0)=0.2090b.P(zz0)=0.7090c.P(-z0z<z0)=0.8472d.P(-z0z<z0)=0.1664e.P(z0zz0)=0.4798f.P(-1<z<z0)

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