Question: A company sent its employees to attend two different English courses. The company is interested in knowing if there is any difference between the two courses attended by its employees. When the employees returned from the courses, the company asked them to take a common test. The summary statistics of the test results of each of the two English courses are recorded in the following table:

a. Identify the parameter(s) that would help the company determine the difference between the two courses.

b. State the appropriate null and alternative hypotheses that the company would like to test.

c. After conducting the hypothesis test at thesignificance level, the company found the p-value. Interpret this result for the company.

Step by step solution

01

(a) Identify the parameters. 

The target parameter will be the population mean and population variance.

02

(b) State the null and alternate hypotheses

The hypothesis that the company would like to test will be:

Null hypothesis: $H_0:{\mu }_1={\mu }_2$, it states there is no difference between the two courses.

Alternate hypothesis: $H_0:{\mu }_1\ne {\mu }_2$, it states there is a difference between the two courses.

03

(c) Give your interpretation. 

Significance level =0.05

p-value=0.325

As the value is more than the significance level, so the null hypothesis will not be rejected. Therefore, it can be concluded that there is no difference between the two courses.

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