Buy-side vs. sell-side analysts' earnings forecasts. Refer to the Financial Analysts Journal (Jul. /Aug. 2008) study of financial analysts' forecast earnings, Exercise 2.86 (p. 112). Recall that data were collected from 3,526 buy-side analysts and 58,562forecasts made by sell-side analysts, and the relative absolute forecast error was determined for each. The mean and standard deviation of forecast errors for both types of analysts are given in the table.

a. Construct a 95% confidence interval for the difference between the mean forecast error of buy-side analysts and the mean forecast error of sell-side analysts.

b. Based on the interval, part a, which type of analysis has the greater mean forecast error? Explain.

c. What assumptions about the underlying populations of forecast errors (if any) are necessary for the validity of the inference, part b?

Short Answer

Expert verified

(a) The 95% confidence interval for the difference between the mean forecast error of buy-side analysts and the mean forecast error of sell-side analysts is (0.8359,0.9640).

(b) The buy-side analyst has a meaner forecast error.

(c) The assumptions for validating part b are as follows:

(i) The samples should be randomly selected.

(ii) The sample size should be sufficiently large enough.

Step by step solution

01

Step-by-Step SolutionStep 1: Formula used

After we get the critical value, find the 95% confidence interval with the use of this formula below:

(x¯1-x¯2)±zα/2s12n1+s22n2

Wherex¯1 is the mean forecast error of the buy-side analystx¯2 is the mean forecast error of the sell-side analysts12 squared the standard deviation of the buy-side analysts22 squared the standard deviation of the sell-side analystn1 total number of samples - buy-side analyst total n2number of samples - sell-side analystzα/2 is the critical values of z-test.

02

To find the level of confidence

Given the below:

One survey was done on financial analysts. The information was gathered from 3,526 buy-side analyst projections and 58,562 sell-side analyst estimates. The information is represented in the table.

n1=3,526,n2=58,562,x¯1=0.85,x¯2=-0.05,s1=1.93ands2=0.85

Let μ1be the mean forecast error of buy-side analysts and

Letμ2be the mean forecast error of sell-side analysts.

Critical value:

The level of confidence is 95%.

α=0.05

α2=0.052

=0.025

Hence, the cumulative area to the left is as follows:

Area to the left - Area to the right

=1-0.025

=0.975

From Table II of the standard normal distribution in Appendix D, the critical value is 1.96

Confidence interval:

CI=(x¯1-x¯2)±za2σ21n1+σ21n2=(0.85-(-0.05))±1.961.9323,526+0.85258,562=0.90±0.0640=(.8359,0.9640)

Thus, the 95%confidence interval for the difference between the mean forecast error of buy-side analysts and the mean forecast error of sell-side analysts is(0.8359,0.9640).

03

(b) Based on the confidence interval, which type of analysis has the greater mean forecast error

The95%confidence interval for the difference between the mean forecast error of buy-side analysts and the mean forecast error of sell-side analysts is(.8359,0.9640).

The interval does not contain 0. So, the mean difference is greater than zero. There is evidence to say that the difference is present between the two groups.

All values in the interval are positive; therefore, it indicates that the mean forecast error of buy-side analysts is more than the mean forecast error of sell-side analysts.

04

(c) Assumptions that make this inference valid

The assumptions for this test are the following:

  • Two samples are randomly selected from the two target populations.
  • Sample sizes are both large.

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Most popular questions from this chapter

Traffic sign maintenance. Refer to the Journal of Transportation Engineering (June 2013) study of traffic sign maintenance in North Carolina, Exercise 8.54 (p. 489). Recall that the proportion of signs on NCDOT-maintained roads that fail minimum requirements was compared to the corresponding proportion for signs on county-owned roads. How many signs should be sampled from each maintainer to estimate the difference between the proportions to within .03 using a 90% confidence interval? Assume the same number of signs will be sampled from NCDOT-maintained roads and county-owned roads

Question: Refer to the Bulletin of Marine Science (April 2010) study of lobster trap placement, Exercise 6.29 (p. 348). Recall that the variable of interest was the average distance separating traps—called trap-spacing—deployed by teams of fishermen. The trap-spacing measurements (in meters) for a sample of seven teams from the Bahia Tortugas (BT) fishing cooperative are repeated in the table. In addition, trap-spacing measurements for eight teams from the Punta Abreojos (PA) fishing cooperative are listed. For this problem, we are interested in comparing the mean trap-spacing measurements of the two fishing cooperatives.

BT Cooperative

93

99

105

94

82

70

86

PA Cooperative

118

94

106

72

90

66

98


Source: Based on G. G. Chester, “Explaining Catch Variation Among Baja California Lobster Fishers Through Spatial Analysis of Trap-Placement Decisions,” Bulletin of Marine Science, Vol. 86, No. 2, April 2010 (Table 1).

a. Identify the target parameter for this study.b. Compute a point estimate of the target parameter.c. What is the problem with using the normal (z) statistic to find a confidence interval for the target parameter?d. Find aconfidence interval for the target parameter.e. Use the interval, part d, to make a statement about the difference in mean trap-spacing measurements of the two fishing cooperatives.f. What conditions must be satisfied for the inference, part e, to be valid?

Given that xis a binomial random variable, compute P(x)for each of the following cases:

a. n= 7, x= 3, p= .5

b. n= 4, x= 3, p= .8

c. n= 15, x= 1, p= .1

Given the following values of x, s, and n, form a 90% confidence interval forσ2

a. x=21,s=2.5,n=50

b. x=1.3,s=0.02,n=15

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Web Check response rates. Response rates to Web checks are generally low, incompletely due to druggies starting but not. I am finishing the check. Survey Methodology (December 2013) delved into the factors that impact response rates. In a designed study, Web druggies were directed to. Share in one of several checks with different formats. For illustration, one format employed a welcome screen with a white background, and another format employed a welcome screen with a red background. The “break-off rates,” i.e., the proportion of tried druggies who break off the check before completing all questions, for the two formats are handed in the table.

White Welcome screen

Red Welcome screen

Number of Web users

198

183

The number who break off the survey

49

37

Break-off rate

.258

.202

Source: R. Haer and N. Meidert, “Does the First Impression Count? Examining the Effect of the Welcome Screen Design on the Response Rate,” Survey Methodology, Vol. 39, No. 2, December 2013 (Table 4.1).

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c. Cipher the test statistic for the test.

d. Find the p- the value of the test.

e. Make the applicable conclusion using α = .10.

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