Homework assistance for accounting students. Refer to the Journal of Accounting Education (Vol. 25, 2007) study of providing homework assistance to accounting students, Exercise 8.18 (p. 468). Recall that one group of students was given a completed homework solution and another group was given only check figures at various steps of the solution. The researchers wanted to compare the average test score improvement of the two groups. How many students should be sampled in each group to estimate the difference in the averages to within .5 point with 99% confidence? Assume that the standard deviations of the test score improvements for the two groups are approximately equal to 1

Short Answer

Expert verified

The required sample size is 54.

Step by step solution

01

Given Information

The standard deviation of two groups are given below

σ1=σ2=1

The sampling error is

SE=.5

02

Z-value

For α=0.01

The z-value is given by

zα2=z0.005=2.58

03

Compute the sample

For, z=2.58,σ1=σ2=1andSE=.5

The sample is calculated as

n1=n2=z0.0052×σ12+σ22SE2=2.582×12+12.52=6.6564×2.25=13.3128.25=53.251254

Therefore, the required sample size is 54.

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