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Chapter 8: Q67E (page 493)

Vulnerability of relying party Web sites. Refer to the Proceedings of the 5th AMC Workshop on Computers & Communication Security (October 2012) study of the vulnerability of relying party (RP) Web sites, Exercise 8.59 (p. 489). Recall that the Web sites were categorized as server-flow or client-flow Web sites. The researchers want to estimate the true difference between the proportion of server-flow Web sites vulnerable to attack and the corresponding proportion of client-flow Web sites with a 95% confidence interval. They want to know how many Web sites of each type they need to sample to obtain an estimate that is no more than .15 from the true difference.

a. Identify the parameter of interest for this study.

Short Answer

Expert verified
  1. \({p_1} - {p_2}\)is the parameter of interest.

Step by step solution

01

Given Information

With a 95% confidence interval, the researchers intend to calculate the actual difference between the proportion of server flow web-sites and client flow websites.

An estimate is no more than.15 off from the actual difference.

02

Parameter

A parameter is a value. It is used to represent a certain characteristics of the population. A parameter is a fixed value. Population characteristic is called parameter.

03

Step 3:

Let\({p_1}\)be the proportion of server flow web-sites

\({p_2}\)be the proportion of server flow web-sites

So, the difference between them is\({p_1} - {p_2}\).

Therefore, \({p_1} - {p_2}\)is the parameter of interest.

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Most popular questions from this chapter

Find the numerical value of

a.6! b.(109)c. (101)d.(63)e.0!

The gender diversity of a large corporation’s board of directors was studied in Accounting & Finance (December 2015). In particular, the researchers wanted to know whether firms with a nominating committee would appoint more female directors than firms without a nominating committee. One of the key variables measured at each corporation was the percentage of female board directors. In a sample of 491firms with a nominating committee, the mean percentage was 7.5%; in an independent sample of 501firms without a nominating committee, the mean percentage was role="math" localid="1652702402701" 4.3% .

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x

10

12

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p

.2

.3

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Independent random samples from two populations with standard deviations σ1=2andσ2=8, respectively, are selected. The sample sizes and the sample means are recorded in the following table:

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b. Calculate the standard error of the sampling distribution for Sample 2.

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agency? Use your answer to part b to justify your conclusion.
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