Two independent random samples are taken from two populations. The results of these samples are summarized in the next table.

  1. Form a 90% confidence interval for\({\mu _1} - {\mu _2}\)

Short Answer

Expert verified
  1. The confidence interval is (3.59, 4.21)

Step by step solution

01

Given Information

The sample sizes are 135 and 148

The means are 12.2 and 8.3.

The variances are 2.1 and 3.0.

02

Confidence Interval

A confidence interval is an interval centered about the sample statistic with width equal to twice the margin of error. If many sample are taken from a population with the sample size then the proportion of the constructed confidence intervals that will contain the population parameter is\(1 - \alpha \) .

03

Confidence interval for \({\mu _d}\)

The confidence interval computed as

\(\begin{aligned}{l}CI &= \left( {{{\bar x}_1} - {{\bar x}_2}} \right) \pm {z_{\frac{\alpha }{2}}}\left( {\sqrt {\frac{{s_1^2}}{{{n_1}}} + \frac{{s_2^2}}{{{n_2}}}} } \right)\\ &= \left( {12.2 - 8.3} \right) \pm {z_{0.05}}\left( {\sqrt {\frac{{2.1}}{{135}} + \frac{3}{{148}}} } \right)\\ &= 3.9 \pm 1.645\left( {.189} \right)\\ = 3.9 \pm .310\\ &= \left( {3.9 - .310,3.9 + .310} \right)\\ &= \left( {3.59,4.21} \right)\end{aligned}\)

Therefore, the confidence interval is (3.59, 4.21)

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Most popular questions from this chapter

Independent random samples from two populations with standard deviations σ1=2andσ2=8, respectively, are selected. The sample sizes and the sample means are recorded in the following table:

Sample 1

Sample 2

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n2=62x¯2=16.23

a. Calculate the standard error of the sampling distribution for Sample 1.

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