Assume that x is a binomial random variable with n = 1000 andp = 0.50. Use a normal approximation to find each of the following probabilities:

a. P(x>500)

b.P(490x<500)

c.P(x>550)

Short Answer

Expert verified
  1. Px>500=0.50
  2. P490x500=0.2357

c.Px>550=0.0008

Step by step solution

01

Given information

x be binomial distribution with n = 1000 and p= 0.50

02

Calculation for the z value

μ=np=1000×0.50=500

σ=np1-p=1000×0.50×1-0.50=1000×0.50×0.50=15.8114

So,

z=x-μσ=x-50015.8114

03

Probability calculation  P(x>500)

a.

P(x>500)=1-P(x<500)=1-P(z<0)=1-0.50=0.50P(x>500)=0.50

Therefore, the required probability is 0.50.

04

Probability calculation  P(490≤x<500)

b.

P490x<500=P<500-Px490=Pz<0-Pz-0.6325=Pz<0-1-Pz-0.6325=0.50-1-0.7357=0.2357P490x<500=0.2357

Therefore, the probability is 0.2357.

05

Probability calculation  P(x>550)

c.

Px>550=1-Px>550=1-Pz<3.1623=1-0.999217=0.0007830.0008Px>550=0.0008

Therefore, the probability is 0.0008.

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