Ranking driving performance of professional golfers.Refer to The Sport Journal(Winter 2007) analysis of anew method for ranking the total driving performance ofgolfers on the PGA tour, Exercise 2.52 (p. 97). Recall thatthe method uses both the average driving distance (yards)and driving accuracy (percent of drives that land in thefairway). Data on these two variables for the top 40 PGAgolfers are saved in the accompanying file. A professionalgolfer is practicing a new swing to increase his averagedriving distance. However, he is concerned that his drivingaccuracy will be lower. Is his concern a valid one? Explain.

Short Answer

Expert verified

Yes, his concern is valid.

Step by step solution

01

Determining the validity of the concern

To answer the question, we will first have to check whether there is any relation between the driving distance and the driving accuracy. Therefore we will first construct a scatterplot using the data given for the two variables.

The data for the two variables is as follows:

The graph is given below:

We can infer from the graph that there is a negative correlation between driving distance and driving accuracy. It is observed that for golfers who had a lengthy driving distance, their driving accuracy was low.

Therefore, the concern of the professional golfer who is trying to increase his driving distance is valid. If he tries to increase his driving distance, his accuracy will reduce.

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Most popular questions from this chapter

Land purchase decision.A buyer for a lumber company must decide whether to buy a piece of land containing 5,000 pine trees. If 1,000 of the trees are at least 40 feet tall, the buyer will purchase the land; otherwise, he won’t. The owner of the land reports that the height of the trees has a mean of 30 feet and a standard deviation of 3 feet. Based on this information, what is the buyer’s decision?

Question: Hotels’ use of ecolabels.Refer to the Journal of Vacation Marketing(January 2016) study of travelers’ familiaritywith ecolabels used by hotels, Exercise 2.42 (p. 94). Recallthat a sample of 392 adult travelers were shown a list of6 different ecolabels, and asked, “How familiar are youwith this ecolabel, on a scale of 1 (not familiar at all) to5 (very familiar).” The mean and standard deviation ofthe responses for each ecolabel are provided in the table.Which of the ecolabels had the most variation in numericalresponses? Explain.

Ecolabel

Mean

Std. Dev.

Energy Star

4.44

0.82

TripAdvisor

3.57

1.38

Green Leaders Audubon

2.41

1.44

International U.S Green

2.28

1.39

Building Council Green Business

2.25

1.39

Green Key

2.01

1.30

Crash tests on new cars.The National Highway Traffic Safety Administration (NHTSA) crash-tests new car models to determine how well they protect the driver and front-seat passenger in a head-on collision. The NHTSA has developed a “star” scoring system for the frontal crash test, with results ranging from one star (*) to five stars (*****). The more stars in the rating, the better the level of crash protection in a head-on collision. The NHTSA crashtest results for 98 cars (in a recent model year) are stored in the accompanying data file.

a. The driver-side star ratings for the 98 cars are summarized in the Minitab printout shown below. Use the information in the printout to form a pie chart. Interpret the graph.

Tally for Discrete Variables: DRIVSTAR

DRIVSTAR

Count

Percent

2

3

4

5

N =

4

17

59

18

98

4.08

17.35

60.20

18.37


b. One quantitative variable recorded by the NHTSA is the driver’s severity of head injury (measured on a scale from 0 to 1,500). The mean and standard deviation for the 98 driver head-injury ratings are displayed in the Minitab printout below. Give a practical interpretation of the mean.
Descriptive Statistics: DRIVHEAD

Variable

N

Mean

StDev

Minimum

Q1

Median

Q3

Maximum

DRIVHEAD

98

603.7

185.4

216.0

475.0

605.0

724.3

1240.0

C. Use the mean and standard deviation to make a statement about where most of the head-injury ratings fall.

d..Find the z-score for a driver head-injury rating of 408. Interpret the result.

Salaries of bachelor’s degree graduates. PayScale, Inc., an online provider of global compensation data, conducts an annual salary survey of bachelor’s degree graduates. Three of the many variables measured by PayScale are the graduate’s current salary, mid-career salary, and the college or university where they obtained their degree. Descriptive statistics are provided for each of the over 400 colleges and universities that graduates attended. For example, graduates of the University of South Florida (USF) had a mean current salary of \(57,000, a median mid-career salary of \)48,000, and a mid-career 90th percentile salary of $131,000. Describe the salary distribution of USF bachelor’s degree graduates by interpreting each of these summary statistics.

Salary offers to MBAs.Consider the top salary offer (in thousands of dollars) received by each member of a sample of 50 MBA students who graduated from the Graduate School of Management at Rutgers, the state university of New Jersey. Descriptive statistics and a box plot for the data are shown on the XLSTAT printouts at the top of the next column. [Note:The “+” on the box plot represents the location of the mean.]

a.Find and interpret the z-score associated with the highest salary offer, the lowest salary offer, and the mean salary offer. Would you consider the highest offer to be unusually high? Why or why not?

b.Based on the box plot for this data set, which salary offers (if any) are suspect or highly suspect outliers?

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