An experiment results in one of the following sample points: E1,E2,E3 orE4 . Find PE4for each of the following cases.

  1. PE1=0.1,PE2=0.2,PE3=0.3
  2. PE1=PE2=PE3=PE4
  3. PE1=PE2=0.1andPE3=PE4

Short Answer

Expert verified
  1. PE4=0.4
  2. PE4=0.25
  3. PE4=0.4

Step by step solution

01

Finding the Probability of the event E4  where  PE1=0.1,PE2=0.2,PE3=0.3

The probability of all the sample points within a sample space is equal to Pi=1

Given PE1=0.1,PE2=0.2,PE3=0.3

PE1+PE2+PE3+PE4=10.1+0.2+0.3+PE4=1PE4=1-0.1+0.2+0.3PE4=0.4

The probability of observing the event E4 is 0.4.

02

Finding the probability of the event E4  where PE1 = PE2 = PE3 = PE4

The probability of all the sample points within a sample space is equal to Pi=1.

Given,

PE1=PE2=PE3=PE4

PE1+PE2+PE3+PE4=14×PE4=1PE4=14PE4=0.25

The probability of observing event E4 is0.25 .

03

Finding the probability of the event E4  where PE1=PE2=0.1  and  PE3=PE4

The probability of all the sample points within a sample space is equal to Pi=1.

Given,

PE1=PE2=0.1and PE3=PE4

PE1+PE2+PE4=10.1+0.1+2×PE4=12×PE4=1-0.1+0.1PE4=0.4

The probability of observing the event E4 is 0.4 .

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