Reliability of gas station air gauges. Tire and automobile manufacturers and consumer safety experts all recommend that drivers maintain proper tire pressure in their cars. Consequently, many gas stations now provide air pumps and air gauges for their customers. In a Research Note(Nov. 2001), the National Highway Traffic Safety Administration studied the reliability of gas station air gauges. The next table gives the percentage of gas stations that provide air gauges that over-report the pressure level in the tire.

a. If the gas station air pressure gauge reads 35 psi, what is the probability that the pressure is over-reported by 6 psi or more?

b. If the gas station air pressure gauge reads 55 psi, what is the probability that the pressure is over-reported by 8 psi or more?

c. If the gas station air pressure gauge reads 25 psi, what is the probability that the pressure is not over-reported by 4 psi or more?

d. Are the events A= {over report by 4 psi or more} and B= {over report by 6 psi or more} mutually exclusive?

e.Based on your answer to part d, why do the probabilities in the table not sum to 1?

Short Answer

Expert verified
  1. The probability is 0.09.
  2. The probability is 0.09.
  3. The probability is 0.84.
  4. The events are not mutually exclusive.
  5. Because column events are not mutually exclusive.

Step by step solution

01

Important formula

The formula for probability isP=FavourableoutcomesTotaloutcomes

02

(a) The probability that the pressure is over-reported by 6 psi or more 

According to the table, the probability is 0.09.

03

(b) The probability that the pressure is over-reported by 8 psi or more

A. To the table, the probability is 0.09.

04

(c) The probability that the pressure is not over-reported by 4 psi or more 

The probability of over-reported is 0.16.

P(notmore6psiormore%)=1P(overreported)=10.16=0.84

So, the probability is 0.84.

05

(d) Event A and B are mutually exclusive

No. The events are not mutually exclusive.

06

(e) The probabilities in the table do not sum to 1

The probabilities in the table did not sum to 1 because column events are not mutually exclusive. Therefore, column events are not mutually exclusive.

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Most popular questions from this chapter

Firefighter glove sizing. Human Factors (December 2015) published a study on how well firefighter gloves fit. In a group of 586 firefighters who reported their glove size, the researchers determined whether the gloves fit well or poorly by gender. The data are summarized in the accompanying table. Consider the gender and glove fit status of a randomly selected firefighter.

a. List the sample points for this experiment.

b. Assign reasonable probabilities to these sample points.

c. Find the probability the firefighter is a female.

d. Find the probability the glove fits well.

e. Find the probability the firefighter is a female and has a well-fitting glove.

f. Find the probability the firefighter is a female or has a well-fitting glove.

Glove Fits Well

Glove Fits Poorly

Totals

Males

415

132

547

Females

19

50

39

Totals

434

152

586

Source: H. Hsiao, et al., “Firefighter Hand Anthropometry and Structural Glove Sizing: A New Perspective,” Human Factors, Vol. 57, No. 8, December 2015 (Table 6).

Consider the experiment depicted by the Venn diagram, with the sample space S containing five sample points. The sample points are assigned the following probabilities:

P (E1) = .20, P (E2) = .30, P (E3)= .30, P (E4) = .10, P (E5) = .10.

a. Calculate P (A), P (B), and P (AB).

b. Suppose we know that event A has occurred, so that the reduced sample space consists of the three sample points in A—namely, E1, E2, and E3. Use the formula for conditional probability to adjust the probabilities of these three sample points for the knowledge that A has occurred [i.e., P (Ei/A)]. Verify that the conditional probabilities are in the same proportion to one another as the original sample point probabilities.

c. Calculate the conditional probabilityP (E1/A)in two ways: (1) Add the adjusted (conditional) probabilities of the sample points in the intersection AB, as these represent the event that B occurs given that A has occurred; (2) use the formula for conditional probability:

P (B/A) =P (AB)P (A)

Verify that the two methods yield the same result.

d. Are events A and B independent? Why or why not?

Home modifications for wheelchair users. The American Journal of Public Health (January 2002) reported on a study of elderly wheelchair users who live at home. A sample of 306 wheelchair users, age 65 or older, were surveyed about whether they had an injurious fall during the year and whether their home features any one of five structural modifications: bathroom modifications, widened doorways/hallways, kitchen modifications, installed railings, and easy-open doors. The responses are summarized the accompanying table. Suppose we select, at random, one of the 306 surveyed wheelchair users.

a. Find the probability that the wheelchair user had an injurious fall.

b. Find the probability that the wheelchair user had all five features installed in the home.

c. Find the probability that the wheelchair user had no falls and none of the features installed in the home.

d. Given the wheelchair user had all five features installed, what is the probability that the user had an injurious fall?

e. Given the wheelchair user had none of the features installed, what is the probability that the user had an injurious fall?

Workers’ unscheduled absence survey. Each year CCH, Inc., a firm that provides human resources and employment law information, conducts a survey on absenteeism in the workplace. The latest CCH Unscheduled Absence Surveyfound that of all unscheduled work absences, 34% are due to “personal illness,” 22% for “family issues,” 18% for “personal needs,” 13% for “entitlement mentality,” and 13% due to “stress.” Consider a randomly selected employee who has an unscheduled work absence.

a. List the sample points for this experiment.

b. Assign reasonable probabilities to the sample points.

c. What is the probability that the absence is due to something other than “personal illness”?

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