Consider the Venn diagram below, were

P(E1)=P(E2)=P(E3)=15,P(E4)=P(E5)=120P(E6)=110,andP(E7)=15

Find each of the following probabilities:

a.P(A)b.P(B)c.P(AB)d.P(AB) e.P(Ac)f.P(Bc)g.P(AAc)h.P(AcB)

Short Answer

Expert verified
  1. 3/4
  2. 7/10
  3. 1
  4. 2/5
  5. 1/4
  6. 7/20
  7. 1
  8. 3/10

Step by step solution

01

By considering the Venn diagram, find the probability

A Venn diagram is a probability diagram with one or more circles inside a rectangle and demonstrates logical relationships between occurrences. In a Venn diagram, the rectangle symbolizes the sample space or the universal set, which is the collection of all possible outcomes.

We know that probability (x)=i=1xxi

Were,

localid="1653540716903" xiare the events belonging to x.

So,

localid="1662214298829" P(A)=P(E1)+P(E2)+P(E3)+P(E5)+P(E6)=15+15+15+120+110=4+4+4+1+220=1520=34

02

Find the probability of P (B)

P(B)=P(E2)+P(E3)+P(E4)+P(E7)=15+15+120+15=4+4+1+420=710

03

Find the probability of P(A∪B)

P(AB)=P(E1)+P(E2)+P(E3)+P(E4)+P(E5)+P(E6)+P(E7)=15+15+15+120+120+110+15=4+4+4+1+1+2+420=2020=1

04

Find the probability

P(AB)=P(E2)+P(E3)=15+15=1+15=25

05

Find the probability

P(Ac)=P(E4)+P(E7)=120+15=1+420=520=14

06

Find the probability

P(Bc)=P(E1)+P(E5)+P(E5)=15+120+110=4+1+220=720

07

Find the probability

P(AAc)=P(A)+P(Ac)-P(AAc)

Here,

P(AAc)=0P(A)=34P(AC)=14

Hence,

P(AAc)=34+14-0=3+14=44=1

08

Find the probability

P(AcB)=P(B)P(AB)=71025=7410=310

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Most popular questions from this chapter

Is a product “green”?A “green” product (e.g., a productbuilt from recycled materials) is one that has minimal impact on the environment and human health. How do consumers determine if a product is “green”? The 2011

ImagePower Green Brands Survey asked this question of more than 9,000 international consumers. The results are shown in the following table.

Reason for saying a product is green

Percentage of consumers

Certification mark on label

45

Packaging

15

Reading information about the product

12

Advertisement

6

Brand we site

4

Other

18

Total

100

a.What method is an international consumer most likely to use to identify a green product?

b.Find the probability that an international consumer identifies a green product by a certification mark on the product label or by the product packaging.

c.Find the probability that an international consumer identifies a green product by reading about the product or from information at the brand’s Web site.

d.Find the probability that an international consumer does not use advertisements to identify a green product.

Are you really being served red snapper? Red snapper is arare and expensive reef fish served at upscale restaurants. Federal law prohibits restaurants from serving a cheaper, look-alike variety of fish (e.g., vermillion snapper or lane snapper) to customers who order red snapper. Researchers

at the University of North Carolina used DNA analysis to examine fish specimens labeled “red snapper” that were purchased from vendors across the country (Nature, July 15, 2004). The DNA tests revealed that 77% of the specimens were not red snapper but the cheaper, look-alike variety of fish.

a. Assuming the results of the DNA analysis are valid, what is the probability that you are actually served red snapper the next time you order it at a restaurant?

b. If there are five customers at a chain restaurant, all who have ordered red snapper, what is the probability that at least one customer is actually served red snapper?

Question: Refer to Exercise 3.35. Use the same event definitions to do the following exercises.

a. Write the event that the outcome is "On" and "High" as an intersection of two events.

b. Write the event that the outcome is "Low" or "Medium" as the complement of an event.

Firefighter glove sizing. Human Factors (December 2015) published a study on how well firefighter gloves fit. In a group of 586 firefighters who reported their glove size, the researchers determined whether the gloves fit well or poorly by gender. The data are summarized in the accompanying table. Consider the gender and glove fit status of a randomly selected firefighter.

a. List the sample points for this experiment.

b. Assign reasonable probabilities to these sample points.

c. Find the probability the firefighter is a female.

d. Find the probability the glove fits well.

e. Find the probability the firefighter is a female and has a well-fitting glove.

f. Find the probability the firefighter is a female or has a well-fitting glove.

Glove Fits Well

Glove Fits Poorly

Totals

Males

415

132

547

Females

19

50

39

Totals

434

152

586

Source: H. Hsiao, et al., “Firefighter Hand Anthropometry and Structural Glove Sizing: A New Perspective,” Human Factors, Vol. 57, No. 8, December 2015 (Table 6).

The three-dice gambling problem. According toSignificance(December 2015), the 16th-century mathematician Jerome Cardan was addicted to a gambling game involving tossing three fair dice. One outcome of interest— which Cardan called a “Fratilli”—is when any subset of the three dice sums to 3. For example, the outcome {1, 1, 1} results in 3 when you sum all three dice. Another possible outcome that results in a “Fratilli” is {1, 2, 5}, since the first two dice sum to 3. Likewise, {2, 3, 6} is a “Fratilli,” since the second die is a 3. Cardan was an excellent mathematician but calculated the probability of a “Fratilli” incorrectly as 115/216 = .532.

a. Show that the denominator of Cardan’s calculation, 216, is correct. [Hint: Knowing that there are 6 possible outcomes for each die, show that the total number of possible outcomes from tossing three fair dice is 216.]

b. One way to obtain a “Fratilli” is with the outcome {1,1, 1}. How many possible ways can this outcome be obtained?

c. Another way to obtain a “Fratilli” is with an outcome that includes at least one die with a 3. First, find the number of outcomes that do not result in a 3 on any of the dice. [Hint: If none of the dice can result in a 3, then there are only 5 possible outcomes for each die.] Now subtract this result from 216 to find the number of outcomes that include at least one 3.

d. A third way to obtain a “Fratilli” is with the outcome {1, 2, 1}, where the order of the individual die outcomes does not matter. How many possible ways can this outcome be obtained?

e. A fourth way to obtain a “Fratilli” is with the outcome {1, 2, 2}, where the order of the individual die outcomes does not matter. How many possible ways can this outcome be obtained?

f. A fifth way to obtain a “Fratilli” is with the outcome {1, 2, 4}, where the order of the individual die outcomes does not matter. How many possible ways can this outcome be obtained? [Hint:There are 3 choices for the first die, 2 for the second, and only 1 for the third.]

g. A sixth way to obtain a “Fratilli” is with the outcome {1, 2, 5}, where the order of the individual die outcomes does not matter. How many possible ways can this outcome be obtained? [See Hintfor part f.]

h. A final way to obtain a “Fratilli” is with the outcome {1, 2, 6}, where the order of the individual die outcomes does not matter. How many possible ways can this outcome be obtained? [See Hintfor part f.]

i. Sum the results for parts b–h to obtain the total number of possible “Fratilli” outcomes.

j. Compute the probability of obtaining a “Fratilli” outcome. Compare your answer with Cardan’s.

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