:A random sample of n = 68 observations is selected from a population withμ=19.6and σ=3.2Approximate each of the following probabilities

a)pX¯19.6

b)pX¯19

c)pX¯20.1

d)p19.2X¯20.6


Short Answer

Expert verified

a)

b)

c)

d)

Step by step solution

01

Given Information

The number of sample size is 68.

The mean and standard deviation are 19.6 and 3.2

02

(a) Compute the probability for given condition

X¯19.6=px¯-μσn19.6-19.63.268=pz00.388=0.5

Therefore,pX¯19.6=0.5

03

(b) Calculation

X¯19=px¯-μσn19-19.63.268=pz-0.60.388=0.061

ThereforepX¯19=0.061

04

(c) Calculation

X¯20.1=px¯-μσn20.1-19.63.268=pz0.50.388=0.098

pX¯19=0.061

05

(d) Calculation

p19.2X¯20.6=p19.2-19.63.268x¯-μσn20.6-19.63.268=p-0.40.388z10.388=pz10.388-pz-0.40.388=0.99-0.15=0.84

Therefore,p19.2X¯20.6=0.84

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