Permeability of sandstone during weathering.Natural stone, such as sandstone, is a popular building construction material. An experiment was carried out to better understand the decay properties of sandstone when exposed to the weather (Geographical Analysis,Vol. 42, 2010). Blocks of sandstone were cut into 300 equal-sized slices and the slices randomly divided into three groups of 100 slices each. Slices in Group A were not exposed to any type of weathering; slices in Group B were repeatedly sprayed with a 10% salt solution (to simulate wetting by driven rain) under temperate conditions; and slices in Group C were soaked in a 10% salt solution and then dried (to simulate blocks of sandstone exposed during a wet winter and dried during a hot summer). All sandstone slices were then tested for permeability, measured in milliDarcies (mD). These permeability values measure pressure decay as a function of time. The data for the study (simulated) are saved in the STONEfile. Measures of central tendency for the permeability measurements of each sandstone group are displayed in the accompanying Minitab printout.

Descriptive Statistics: PermA, PermB, PermC

Variable

N

Mean

Median

Mode

N for Mode

PermA

100

73.62

70.45

59.9, 60, 60.1, 60.4

2

PermB

100

128.54

139.30

146.4, 146.6, 147.9, 148.3

3

PermC

100

83.07

78.65

70.9

3

The data contain atleast 5 mode value.

Only the smallest 4 are shown

a.Interpret the mean and median of the permeability measurements for Group A sandstone slices.

b.Interpret the mean and median of the permeability measurements for Group B sandstone slices.

c.Interpret the mean and median of the permeability measurements for Group C sandstone slices.

d.Interpret the mode of the permeability measurements for Group C sandstone slices.

e.The lower the permeability value, the slower the pressure decay in the sandstone over time. Which type of weathering (type B or type C) appears to result in faster decay?

Short Answer

Expert verified

a. Mean = 73.62, Median = 70.45

b. Mean = 128.54, Median = 139.30

c. Mean = 83.07, Median = 78.65

d. Mode = 70.9

e. Type B

Step by step solution

01

Interpreting the mean and median of the permeability measurements for Group A 

The average permeability for Group A of sandstone slices is 73.62 mD. When the sandstone is not exposed to any weathering, its permeability level is around 73.62 mD over time.

The median for Group A is 70.45 mD. That implies 50% of sandstone slices in no weathering condition will have permeability levels below 70.45 mD and, 50% will have more than that.

02

Understanding the mean and median of the permeability measurements for Group B

The mean here is 128.54 mD. Therefore we know that when the sandstone is exposed to the conditions in Group B, the average rate of permeability is 128.54 mD.

As the median permeability for Group B is 139.30 mD, it indicates that half slices will have less permeability than 139.30 mD and half have permeability more than tha

03

Illustrating the meaning of mean and median for the permeability measurements of Group C

83.07 mD is the mean permeability in Group C. Indicating the average rate of permeability in weather conditions created for Group C.

The median being 78.65 mD indicates that 50% slices may have permeability levels above and 50% may have permeability levels below 78.65 mD.

04

Explaining the mode of the permeability measurements for Group C 

70.9 mD is the mode because it was repeated a maximum number of times (3) in the group. We can infer from this that when rocks are exposed to weather conditions, such as in Group C, the most likely permeability rate will be 70.9 mD.

05

Determining which type of weathering leads to faster decay

Type B weathering appears in faster decay because the mean permeability value is higher for type B. Also, the mode values are higher than type C, indicating that the most common permeability values are higher and that more stones under type B weathering are likely to have higher values.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Software millionaires and birthdays. Refer to Exercise 11.23 (p. 655) and the study of software millionaires and their birthdays. The data are reproduced on p. 663.

a. Find SSE s2and s for the simple linear regression model relating the number (y) of software millionaire birthdays in a decade to the total number (x) of U.S. births.

b. Find SSE s2and s for the simple linear regression model relating the number (y) of software millionaire birthdays in a decade to the number (x) of CEO birthdays.

c. Which of the two models' fit will have smaller errors of prediction? Why?

Decade

Total U.S. Births (millions)

Number of Software Millionaire Birthdays

Number of CEO Birthdays (in a random sample of 70 companies from the Fortune 500 list)

1920

28.582

3

2

1930

24.374

1

2

1940

31.666

10

23

1950

40.530

14

38

1960

38.808

7

9

1970

33.309

4

0

Do nice guys really finish last in business? Refer to the Nature (March 20, 2008) study of whether “nice guys finish last” in business, Exercise 11.18 (p. 653). Recall that college students repeatedly played a version of the game “prisoner’s dilemma,” where competitors choose cooperation, defection, or costly punishment. At the conclusion of the games, the researchers recorded the average payoff and the number of times punishment was used for each player. Based on a scatter plot of the data, the simple linear regression relating average payoff (y) to punishment use (x) resulted in SSE = 1.04.

a. Assuming a sample size of n = 28, compute the estimated standard deviation of the error distribution, s.

b. Give a practical interpretation of s.

The equation for a straight line (deterministic model) is

y=β0+β1x

If the line passes through the point (-2, 4), then x = -2, y = 4 must satisfy the equation; that is,

4=β0+β1(-2)

Similarly, if the line passes through the point (4, 6), then x = 4, y = 6 must satisfy the equation; that is,

6=β0+β1(4)

Use these two equations to solve for and ; then find the equation of the line that passes through the points (-2, 4) and (4, 6).

Give the slope and y-intercept for each of the lines graphed in Exercise 11.1.

Do the accompanying data provide sufficient evidence that a straight line is useful for characterizing the relationship between x and y?

X424324
Y165324
See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free