The equation for a straight line (deterministic model) is

y=β0+β1x

If the line passes through the point (-2, 4), then x = -2, y = 4 must satisfy the equation; that is,

4=β0+β1(-2)

Similarly, if the line passes through the point (4, 6), then x = 4, y = 6 must satisfy the equation; that is,

6=β0+β1(4)

Use these two equations to solve for and ; then find the equation of the line that passes through the points (-2, 4) and (4, 6).

Short Answer

Expert verified

β0=143, β1=-13

3y = 14 + x

Step by step solution

01

Introduction

In geometry, a line is essentially a zero-width object that extends on both sides. A straight line is a line that does not have any curves. A straight line is one that has no curves and extends to both sides to infinity.

02

Finding  β0 and β1

Equation of a straight line:

y=β0+β1x

If a line passes through, (2, 4),

4=β0+β1(-2).........(1)

If a line passes through (4, 6),

6=β0+β1(4).........(2)

Solving equations (1) & (2) simultaneously, we get

β0+β1(-2)-4=β0+β1(4)-66β1=-2β1=-26β1=-13

Therefore, we get

4=β0+-13(-2)4+23=β0β0=12+23β0=143

03

Finding the equation that passes through the points (-2, 4) and (4, 6) 

y=β0+β1xy=143+13xy=14+x33y=14+x

Therefore, the required equation is 3y = 14 + x.

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