Pat wants to compare the cost of one- and two-bedroom apartments in the area of her college campus. She collects data for a random sample of 10 advertisements of each type. The table below shows the rents (in dollars per month) for the selected apartments.

Pat wonders if two-bedroom apartments rent for significantly more, on average than one-bedroom apartments. She decides to perform a test of H0:μ1=μ2 versus Ha:μ1<μ2, where μ1 and μ2 are the true mean rents for all one-bedroom and two-bedroom aparaments, respectively, near the campus.

(a) Name the appropriate test and show that the conditions for carrying out this test are met.

(b) The appropriate test from part (a) yields a P-value of 0.058. Interpret this P-value in context.

(c) What conclusion should Pat draw at theα=0.05 significance level? Explain.

Short Answer

Expert verified

a)Two-sample t-test

b)P=5.8%

c)There is not sufficient evidence to support the claim that two-bedroom apartments rent for significantly more, on average than one-bedroom apartments.

Step by step solution

01

Part(a) Step 1: Given Information

In general:

One proportion: one-sample ztest/interval

Two proportions: two-sample ztest/interval

One means: one-sample ttest/interval

Two means: two-sample ttest/interval or paired ttest/interval

Use a test if you want to test for a difference, equality, increase or decrease. Use an interval if you want to estimate an interval in which the true value lies.

The two-sample t test for a population mean the difference

because we are interested in testing the means of two samples.

02

Part(a) Step 2: Explanation

There are three conditions for the test: Random, Normal, Independent

Random: Satisfied, because the samples are given to be random samples.

Normal: Satisfied, because the histograms of the samples do not show strong skewness or outliers.

Independent: Satisfied, because the sample size is less than 10%of the population size.

Thus we note that all three conditions have been satisfied.

03

Part(b) Step 1: Given Information

H0:μ1=μ2

Ha:μ1<μ2

P=0.058=5.8%

04

Part(b) Step 2: Explanation

The P-value is the probability of obtaining the value of the test statistic, or a value more extreme if the null hypothesis H0is true.

This then means that if the population means are equal, then the probability of obtaining two samples with a difference as in the given two samples (or a more extreme difference) is localid="1650520353140" 5.8%.

05

Part(c) Step 1: Given Information

H0:μ1=μ2

Ha:μ1<μ2

P=0.058=5.8%(Exercise13b)

06

Part(c) Step 2: Explanation

If the P-value is smaller than the significance level, reject the null hypothesis:

P=0.058>0.05Fail to rejectH0

There is not sufficient evidence to support the claim that two-bedroom apartments rent for significantly more, on average than one-bedroom apartments.

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Most popular questions from this chapter

A large university is considering the establishment of a schoolwide recycling program. To gauge interest in the program by means of a questionnaire, the university takes separate random samples of undergraduate students, graduate students, faculty, and staff. This is an example of what type of sampling design?

(a) Simple random sample

(b) Stratified random sample

(c) Convenience sample

(d) Cluster sample

(e) Systematic sample

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Which of the following is false?

(a) A measure of center alone does not completely describe the characteristics of a set of data. Some measure of spread is also needed.

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(d) Between the range and the interquartile range, the IQR is a better measure of spread if there are outliers.

(e) If a distribution is skewed, the median and interquartile range should be reported rather than the mean and standard deviation.

Down the toilet A company that makes hotel toilets claims that its new pressure-assisted toilet reduces the average amount of water used by more than 0.5a gallon per flush when compared to its current model. To test this claim, the company randomly selects 30toilets of each type and measures the amount of water that is used when each toilet is flushed once. For the current-model toilets, the mean amount of water used is1.64a gal with a standard deviation of 0.29gal. For the new toilets, the mean amount of water used is 1.09galwith a standard deviation of 0.18gal.

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