The elderly fear crime more than younger people, even though they are less likely to be victims of crime. One study recruited separate random samples of 56black women and 63black men over the age of 65from Atlantic City, New Jersey. Of the women, 27said they “felt vulnerable” to crime; 46of the men said this.

(a) Construct and interpret a 90%confidence interval for the difference in population proportions (men minus women).

(b) Does your interval from part (a) give convincing evidence of a difference between the population proportions? Explain.

Short Answer

Expert verified

(a) We are 90%confident that the proportion difference is between 0.105and 0.391.

(b) Yes. the interval from part (a) gives convincing evidence of a difference between the population proportions

Step by step solution

01

Part(a) Step 1: Given Information

Given

x1=46

n1=63

x2=27

n2=56

02

Part(a) Step 2: Explanation

The sample proportion is calculated by dividing the sample size by the number of successes:

p^1=x1n1=46630.730

p^2=x2n2=27560.482

For confidence level 1-α=0.90, determine zα/2=z0.05using table II (look up 0.05in the table, the z-score is then the found z-score with the opposite sign):

zα/2=1.645

The endpoints of the confidence interval for p1-p2are then:

localid="1650449367380" p^1-p^2-zα/2·p^11-p^1n1+p^21-p^2n2=(0.730-0.482)-1.6450.730(1-0.730)63+0.482(1-0.482)560.105

localid="1650449382868" p^1-p^2+zα/2·p^11-p^1n1+p^21-p^2n2=(0.730-0.482)+1.6450.730(1-0.730)63+0.482(1-0.482)560.391

03

Part(b) Step 1: Given Information

Given

x1=46

n1=63

x2=27

n2=56

04

Part(b) Step 2: Explanation

Result part (a)

(0.105,0.391)

The confidence interval does not contain 0, then it is very unlikely that the population proportions are equal and thus there is convincing evidence of a difference between the population proportions.

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