In an experiment to learn whether Substance M can help restore memory, the brains of 20rats were treated to damage their memories. The rats were trained to run a maze. After a day, 10rats (determined at random) were given M and 7of them succeeded in the maze. Only 2of the 10control rats were successful. The two-sample z test for “no difference” against “a significantly higher proportion of the M group succeeds”

(a) gives z=2.25,P<0.02

(b) gives z=2.60,P<0.005

(c) gives z=2.25,P<0.04but not <0.02

(d) should not be used because the Random condition is violated

(e) should not be used because the Normal condition is violated.

Short Answer

Expert verified

The two-sample z test for “no difference” against “a significantly higher proportion of the M group succeeds” option (e) should not be used because the Normal condition is violated.

Step by step solution

01

Given information

The treated rats to damage their memories =20

Number of rats given M =10

Succeeded rats in maze=7

successful rats=2

02

Explanation

To achieve the Normal requirement, the number of failures in the number of successes in both samples must be greater than 10.

The Normal criterion is not met because there are 7successes in the first sample and 2successes in the second sample.

As a result, it shouldn't be used because the Normal condition has been broken.

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